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uysha [10]
2 years ago
5

How to type the plus sign +

Computers and Technology
2 answers:
zmey [24]2 years ago
7 0

Answer:

you just did it. its on da keyboard

Explanation:

hold shift and click the equal sign

Shift + = = +

CaHeK987 [17]2 years ago
3 0

Answer:

For Windows and Mac OS

The easiest way would be to open your Character Map.  

Explanation:

Windows: How do I view a Character Map?

To start Character Map and see all the available characters for a particular font, click Start, point to Programs, point to Accessories, point to System Tools, and then click Character Map.

Mac OS: The easiest is to display the Mac OS Characters palette – just press [Command] + [Option] + [T], or [⌘] + [⌥] + [T]. You can then browse through various symbols and special characters, and simply double-click anyone to insert it into your current document.

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A robot worker and a human worker are both vulnerable to
Lady bird [3.3K]

Answer:

fire

Explanation:

4 0
3 years ago
Wap in java to complete the following (16*1) +(14*2) +(12*3) +(10*4) +(8*5) +(6*6) +(4*7)​
vladimir1956 [14]

Answer:

It goes like:

public class Program

{

public static void main(String[] args)

{

int j=18;

int sum=0;

for (int i =1; i<7; i++)

{

sum=sum+(i*(j-2));

j=j-2;

}

System.out.println(sum);

}

}

Explanation:

<u>Variables used: </u>

j : controls the first number in product and decreases by 2 each time the loop runs.

sum: saves the values of addition as the loop runs.

3 0
2 years ago
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
3 years ago
What is the most flexible way to modify a report?
Vesna [10]

Answer: Use the Design view

Explanation: Using a Design view to modify a report is the most flexible way to modify a report as opposed to a layout view which is another way to modify a report .  The design view  is flexible in the sense that it provides a more outlined structured view of your report that you can see the header and footer for the report. it also affords you the ability to control your  report in terms of changing many properties, adjusting images, labels  and editing  text box, etc.

8 0
2 years ago
it is a program a personal computer microprocessor uses to get the computer system started after you turn it on​
Fofino [41]

Explanation:

please repeat your question

5 0
2 years ago
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