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Elden [556K]
3 years ago
13

4(x+3)=3(3x-1)

Mathematics
1 answer:
zhuklara [117]3 years ago
5 0
24=26 is the answer... want mhe 2 show you?
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∠1 and ∠2 are complementary angles. m∠1 is 5y+32 and m∠2 is 7y-14. Find m∠2 & show your work.
Ainat [17]
  • m<1+m<2=90

\\ \sf\longmapsto 5y+32+7y-14=90

\\ \sf\longmapsto 12y+18=90

\\ \sf\longmapsto 12y=72

\\ \sf\longmapsto y=6

  • m<2=7(6)-14=42-14=28[/tex]
7 0
3 years ago
Read 2 more answers
Which number is greater: 87 or 13.688?how do you know?
just olya [345]
When comparing two numbers, you usually start by comparing the numbers on the left of the decimal point, if you find one of them greater than the other, then you've got your answer ready. If the numbers on the left of the point are equal, then you start comparing the decimal part.

In the two numbers given, we have 87 and 13.688. We start by comparing the numbers before the point, we will find that these numbers are 87 and 13.
Comparing these two, we can see that 87 is greater than 13.

Therefore: 87 is greater than 13.688
7 0
3 years ago
Read 2 more answers
Write the equation of the line that passes through the points (2 , -1) and has a slope of - 3​
svetlana [45]

Answer:

y=-3x+5

Step-by-step explanation:

y=mx+b

m=slope or gradient (=-3)

y=-3x+b  

Add your points

(2, -1)

-1=(-3 x 2)+b

-1= -6+b

-1+6=b

b=5

y=-3x+5

5 0
3 years ago
Read 2 more answers
Select the correct description of the graph of the inequality: I &gt; 3.5
Norma-Jean [14]

Answer:

gfygou

Step-by-step explanation:

4 0
3 years ago
Use the Midpoint Rule with n = 10 to approximate the length of c(t) = (5 + sin(4t), 6 + sin(7t)) for 0 ≤ t ≤ 2π. (Round your ans
sukhopar [10]

Answer:

  34.43

Step-by-step explanation:

A differential of length in terms of t will be ...

  dL(t) = √(x'(t)^2 +y'(t)^2)

where ...

  x'(t) = 4cos(4t)

  y'(t) = 7cos(7t)

The length of c(t) will be the integral of this differential on the interval [0, 2π].

Dividing that interval into 10 equal pieces means each one has a width of (2π)/10 = π/5. The midpoint of pieces numbered 1 to 10 will be ...

  (π/5)(n -1/2), so the area of the piece will be ...

  sub-interval area ≈ (π/5)·dL((π/5)(n -1/2))

It is convenient to let a spreadsheet or graphing calculator do the function evaluation and summing of areas.

__

The attachment shows the curve c(t) whose length we are estimating (red), and the differential length function (blue) we are integrating. We use the function p(n) to compute the midpoint of the sub-interval. The sum of sub-interval areas is shown as 34.43.

The length of the curve is estimated to be 34.43.

8 0
3 years ago
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