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Eduardwww [97]
3 years ago
14

Alisha hiked a trail that was 9/10 mile and Joseph hiked a trail that was 5/10 mile. How much farther did Alisha hike than Josep

h?
Mathematics
1 answer:
Elenna [48]3 years ago
8 0

Answer:

4/10 or 2/5 of a mile more.

Step-by-step explanation:

Since the denominators are the same, all you have to do is subtract the numerators.

9-5=10.

Therefore, Alisha hiked 2/5 of a mile further than Joseph.

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Can someone help me on this!!!​
Amiraneli [1.4K]

Answer:

dates

Step-by-step explanation:

bestie it is dates i am sure of it.

4 0
3 years ago
25 children are standing in a line to play a game. they are given numbers 1 to 25 to identify themselves. then, every 4th child
MrRa [10]

Children who came forward are numbered 4, 8, 12, 16, 20, 24 i.e. multiples of 4 ≤25  

Given that 25 kids are waiting in line to play a game. They are assigned numbers ranging from 1 to 25 to identify themselves. Then, every fourth child in line is asked to step forward.

Every fourth child in the line is asked to step forward

then, 4th child,8th child,12th child,16th child,20th child,24 child will come forward as if 4,8,12,16,20,24 are the numbers which are multiples of 4 ≤25

Children who came forward are numbered 4, 8, 12, 16, 20, 24 i.e. multiples of 4 ≤25

Learn more about numbers here:

brainly.com/question/17429689

#SPJ4

8 0
2 years ago
The height in feet of a flying disc in t seconds is modeled by the equation h(t) = −4.5t2 + 19.6t + 3. What does the 3 in the eq
dalvyx [7]

Answer:

  • 3 feet is the start point

Step-by-step explanation:

<u>Function given:</u>

  • h(t) = −4.5t2 + 19.6t + 3

At t =0 we get h(0) = 3. This is called y-intercept

It is the start point indicating the disc was thrown at 3 feet height

7 0
3 years ago
A certain flight arrives on time 8484 percent of the time. Suppose 143143 flights are randomly selected. Use the normal approxim
Troyanec [42]

Answer:

a) P(x=108)=0.0020

b) P(x≥108)=0.9980

c) P(x<124)=0.7794

d) P(124≤x≤128)=0.1925

Step-by-step explanation:

We know the population proportion, that is p=0.84.

We take a sample of size n=143.

We will use the normal approximation to the binomial distribution to model this problem.

The mean and standard deviation of the normal approximation to the binomial distribution will be:

\mu=np=143*0.84=120.12\\\\\sigma=\sqrt{np(1-p)}=\sqrt{143*0.84*0.16}=\sqrt{19.22}=4.38

a) We have to calculate the probability that exactly 108 flights are on time.

As the normal distribution considers the random variable to be continous, we have to apply the continuity correction factor.

In this case, the probability of 108 flights on time can be calculated as P(107.5<x<108.5):

P(x=108)=P(107.5

b) Now we have to calculate that at least 108 flights are on time.

As the probability includes 108, the continuity factor will indicates that we calculate P(x>107.5). The z-value for x=107.5 has been already calculated in point a:

P(x\geq108)=P(x>107.5)=P(z>-2.88)=0.9980

c) We have to calculate the probability that fewer than 124 flights are on time. According to the continuity factor, we have to calculate the probability P(x<123.5), as the flight number 124 is not included in the interval.

P(x

d) We have to calculate the probability that between 124 and 128 flights, inclusive, are on time.

This interval corresponds to the probability P(123.5<x<128.5)

P(123.5

5 0
4 years ago
What is the transformation of A(6, 4) when dilated by a scale factor of 12,
kramer
A(6,4) I know that OA and all that is something I do not know
6 0
2 years ago
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