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AlekseyPX
2 years ago
13

Slope intercept for x + 2y = -8

Mathematics
1 answer:
BabaBlast [244]2 years ago
4 0
Y= -1/2x-8 is the answer just algebraically rearranged
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Suppose that is an angleand y is not in the first quadrant. Compute the exact value of secyYou do not have to rationalize the de
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ANSWER :

The answer is :

-\frac{5\sqrt{10}}{9}

EXPLANATION :

Note that cotangent is only positive when the angle is in the first or third quadrant.

Since y is not in the first quadrant, it must be in the third quadrant.

So the x and y are both negative.

An angle with a terminal point (x, y)

The cotangent is x/y

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\cot\gamma=\frac{9}{13}=\frac{x}{y}

Since x and y are both negatives, x = -9 and y = -13

We can have the triangle :

The hypotenuse will be :

\begin{gathered} c=\sqrt{(-9)^2+(-13)^2} \\ c=5\sqrt{10} \end{gathered}

We are asked to find the value of sec y.

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The secant is :

\sec\gamma=\frac{\text{ hypotenuse}}{x}

The hypotenuse is 5√10 and x = -9

The value of sec will be :

\begin{gathered} \sec\gamma=\frac{5\sqrt{10}}{-9} \\  \\ =-\frac{5\sqrt{10}}{9} \end{gathered}

6 0
1 year ago
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