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ololo11 [35]
2 years ago
7

An initial population of 415 quail increases at an annual rate of 32%. Write an exponential function to model the quail populati

on. What will the approximate population be after 5 years?
Mathematics
1 answer:
hichkok12 [17]2 years ago
5 0

Answer:

Below in bold.

Step-by-step explanation:

The population P will increase by a factor of 1.32 each year.

The function is

P = 415(1.32)^t  where t is the time in years.

After 5 years:

P = 415(1.32)^5  = 1663.

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Hurry!!!Need help with this question!!!<br> If p(x) = 2x2 – 4x and q(x) = x – 3, what is (p*h)(x)?
nignag [31]
Hey there,

If p(x) = 2x2 – 4x and q(x) = x – 3, what is (p*h)(x)?

Based on my understanding, I believe that your correct answer would
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Hope this helps.
4 0
3 years ago
100.
Ratling [72]

Check the picture below.

so our bases are "d" and "d+a+b", and a height of "c".

\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(x+y)}{2}~~ \begin{cases} x,y=\stackrel{parallel~sides}{bases}\\ h~~~=height\\ \cline{1-1} x=d\\ y=d+a+b\\ h=c\\ A=(d+b)c \end{cases}\implies (d+b)c=\cfrac{c[d+(d+a+b)]}{2} \\\\\\ 2(d+b)c=c[d+(d+a+b)]\implies 2dc+2bc=c(2d+a+b)

\bf ~~\begin{matrix} 2dc \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+2bc=~~\begin{matrix} 2dc \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+ac+bc\implies 2bc=ac+bc\implies 2bc=c(a+b) \\\\\\ \cfrac{2b~~\begin{matrix} c \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} c \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=a+b\implies 2b=a+b\implies 2b-b=a\implies \blacktriangleright b=a \blacktriangleleft

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4 years ago
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I don't know who needs to hear this but I wanted to hopefully reach out to someone.
Y_Kistochka [10]

Answer:

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