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Minchanka [31]
3 years ago
14

Kevin is driving a truck filled with mulch. The mulch is packed in a container 20 feet long, 15 feet wide, and 12 feet tall. If

each cubic foot of mulch weighs 5.6 pounds, what is the weight of the mulch in the truck?
Mathematics
2 answers:
Reil [10]3 years ago
5 0

Answer:

The answer is 3605

Step-by-step explanation:

That is the answer because you have to do 20x15x12 and that will equal 3600 and then you do 3600+5.6 and that will equal 3605

Ainat [17]3 years ago
3 0

Answer:

20160 pounds

Step-by-step explanation:

20 * 15 * 12 = 3600 feet^3 = Volume

3600 feet^3 * 5.6 pounds = 20160 lbs

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Please help me. Please....
Nadusha1986 [10]

Answer:

20

Step-by-step explanation:

1/2(a+b)=180

1/2(6+12)=18

1/2(18)=180

9/9=180/9

=20

8 0
3 years ago
At a collage bookstore Clara purchased a math textbook and a novel that cost a total of $54 not including tax if the price of th
diamong [38]

Answer:

m+n=54 and m=3n+8 is the system of equations that could be used to determine the price of each book.

Step-by-step explanation:

Given,

Total cost of maths book and novel = $54

Let,

Cost of maths book = m

Cost of novel = n

According to given statement;

m+n=54      Eqn 1

the price of the math textbook, m, is $8 more than 3 times the price of the novel

m = 3n+8     Eqn 2

m+n=54 and m=3n+8 is the system of equations that could be used to determine the price of each book.

Step-by-step explanation:

3 0
3 years ago
If 13cos theta -5=0 find sin theta +cos theta / sin theta -cos theta​
Ivahew [28]

Step-by-step explanation:

<h3>Need to FinD :</h3>

  • We have to find the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0.

\red{\frak{Given}} \begin{cases} & \sf {13\ cos \theta\ -\ 5\ =\ 0\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \big\lgroup Can\ also\ be\ written\ as \big\rgroup} \\ & \sf {cos \theta\ =\ {\footnotesize{\dfrac{5}{13}}}} \end{cases}

Here, we're asked to find out the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0. In order to find the solution we're gonna use trigonometric ratios to find the value of sinθ and cosθ. Let us consider, a right angled triangle, say PQR.

Where,

  • PQ = Opposite side
  • QR = Adjacent side
  • RP = Hypotenuse
  • ∠Q = 90°
  • ∠C = θ

As we know that, 13 cosθ - 5 = 0 which is stated in the question. So, it can also be written as cosθ = 5/13. As per the cosine ratio, we know that,

\rightarrow {\underline{\boxed{\red{\sf{cos \theta\ =\ \dfrac{Adjacent\ side}{Hypotenuse}}}}}}

Since, we know that,

  • cosθ = 5/13
  • QR (Adjacent side) = 5
  • RP (Hypotenuse) = 13

So, we will find the PQ (Opposite side) in order to estimate the value of sinθ. So, by using the Pythagoras Theorem, we will find the PQ.

Therefore,

\red \bigstar {\underline{\underline{\pmb{\sf{According\ to\ Question:-}}}}}

\rule{200}{3}

\sf \dashrightarrow {(PQ)^2\ +\ (QR)^2\ =\ (RP)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ (5)^2\ =\ (13)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ 25\ =\ 169} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 169\ -\ 25} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 144} \\ \\ \\ \sf \dashrightarrow {PQ\ =\ \sqrt{144}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{PQ\ (Opposite\ side)\ =\ 12}}}}_{\sf \blue{\tiny{Required\ value}}}}

∴ Hence, the value of PQ (Opposite side) is 12. Now, in order to determine it's value, we will use the sine ratio.

\rightarrow {\underline{\boxed{\red{\sf{sin \theta\ =\ \dfrac{Opposite\ side}{Hypotenuse}}}}}}

Where,

  • Opposite side = 12
  • Hypotenuse = 13

Therefore,

\sf \rightarrow {sin \theta\ =\ \dfrac{12}{13}}

Now, we have the values of sinθ and cosθ, that are 12/13 and 5/13 respectively. Now, finally we will find out the value of the following.

\rightarrow {\underline{\boxed{\red{\sf{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}}}}}}

  • By substituting the values, we get,

\rule{200}{3}

\sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\Big( \dfrac{12}{13}\ +\ \dfrac{5}{13} \Big)}{\Big( \dfrac{12}{13}\ -\ \dfrac{5}{13} \Big)}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\dfrac{17}{13}}{\dfrac{7}{13}}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{13} \times \dfrac{13}{7}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{\cancel{13}} \times \dfrac{\cancel{13}}{7}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{7}}}}}_{\sf \blue{\tiny{Required\ value}}}}

∴ Hence, the required answer is 17/7.

6 0
3 years ago
Write an equation of the line with slope -2 and passing through (3,1) in slope-intercept form
Vinvika [58]

Answer:

y=-2x+7

Step-by-step explanation:

Hi there!

The form of slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept

We are given the slope (-2) and a point (3,1)

We can immediately substitute -2 as the slope in the equation

y=-2x+b

Now we need to find b

Because the line will pass through the point (3,1), we can use it to solve for b

Substitute 3 as x and 1 as y

1=-2(3)+b

multiply

1=-6+b

add 6 to both sides to isolate b

7=b

Substitute 7 as b into the equation

The line is <u>y=-2x+7</u>

Hope this helps!

8 0
3 years ago
Please help me with this
julsineya [31]
X is 19 and y is 84.
3 0
3 years ago
Read 2 more answers
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