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natita [175]
2 years ago
9

Factor x3 x2 x 1 by grouping. what is the resulting expression? (x2)(x 1) (x2 1)(x) (x2 1)(x 1) (x3 1)(x 1)

Mathematics
1 answer:
nika2105 [10]2 years ago
8 0

The result of factoring the expression x³ + x² + x + 1 by grouping is (x²+ 1)(x + 1)

<h3>How to factor the expression?</h3>

The expression is given as:

x³ + x² + x + 1

Group the terms of the expression in 2's

x³ + x² + x + 1 = x²(x + 1) + 1(x + 1)

Factor out x + 1 in the expression

x³ + x² + x + 1 = (x²+ 1)(x + 1)

The above means that the result of factoring the expression x³ + x² + x + 1 by grouping is (x²+ 1)(x + 1)

Read more about factoring expressions at:

brainly.com/question/723406

#SPJ4

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Javier walks from his house to the zoo at a constant
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Answer:

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Step-by-step explanation:

I don´t understand the question

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3 years ago
Thirty students at Eastside High School took the SAT on the same Saturday. Their raw scores are given next. 1,450 1,620 1,800 1,
IRISSAK [1]

Answer:

Number of students who scored atleast 1700 but less Than 2100 = 17

Step-by-step explanation:

Given the data :

1,450 1,620 1,800 1,740 1,650 1,800 2,010 1,780 1,840 1,490 1,620 1,480 2,390 1,640 1,830 1,710 1,900 1,910 1,950 1,820 1,590 2,350 2,260 1,870 1,530 1,950 2,000 1,830 1,980 2,100

Class interval __ Frequency

1400 - 1599 ____ 5

1600 - 1799 ____ 7

1800 - 1999 ____12

2000 - 2199 ___ 3

2200 - 2399 ___ 3

Number of students who scored atleast 1700 but less Than 2100 = 17

8 0
3 years ago
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Misha Larkins [42]
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4 0
3 years ago
What two rational expressions sum to 2x+3/x^2-5x+4
Anni [7]

Answer:

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

Step-by-step explanation:

Given the rational expression: \frac{2x + 3}{x^2 - 5x + 4}, to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

x^2 - 5x + 4

x^2 - 4x - x + 4

(x^2 - 4x) - (x + 4)

x(x - 4) - 1(x - 4)

(x- 1)(x - 4)

Thus, we now have: \frac{2x + 3}{(x- 1)(x - 4)}

Step 2: Apply the concept of Partial Fraction

Let,

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

Multiply both sides by (x - 1)(x - 4)

\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4) = (\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)

2x + 3 = A(x - 4) + B(x - 1)

Step 3:

Substituting x = 4 in 2x + 3 = A(x - 4) + B(x - 1)

2(4) + 3 = A(4 - 4) + B(4 - 1)

8 + 3 = A(0) + B(3)

11 = 3B

\frac{11}{3} = B

B = \frac{11}{3}

Substituting x = 1 in 2x + 3 = A(x - 4) + B(x - 1)

2(1) + 3 = A(1 - 4) + B(1 - 1)

2 + 3 = A(-3) + B(0)

5 = -3A

\frac{5}{-3} = \frac{-3A}{-3}

A = -\frac{5}{3}

Step 4: Plug in the values of A and B into the original equation in step 2

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

7 0
3 years ago
The quotient of 12 and the opposite of 3 plus the product of the opposite of 14 and 4
Fynjy0 [20]
Putting this into an equation, it would be (12 ÷ -3) + - (14 x 4)
-4 + -56 = -60
4 0
3 years ago
Read 2 more answers
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