Answer:
26.2 units
Step-by-step explanation:
We are given the points/vertices
A(6, 3),
B(6, - 2) , and
C(- 4, 3)
Step two
Let us find the distances between the given points/vertices
A-B =A(6, 3) to B(6,-2)
d=√((x2-x1)²+(y2-y1)²)
Substitute
d=√((6-6)²+(-2-3)²)
d=√(-2-3)²)
d=√(-5)²)
d=5 units
B-C=B(6, - 2) to C(-4, 3)
d=√((x2-x1)²+(y2-y1)²)
Substitute
d=√((-4-6)²+(3+2)²)
d=√(-10)²+(5)²)
d=√100+25
d=√125
d=11.2 units
C-A=C(-4, 3) to A(6, 3)
d=√((x2-x1)²+(y2-y1)²)
Substitute
d=√((6+4)²+(3-3)²)
d=√(10)²
d=√100
d=10 units
Hence the perimeter is 5+11.2+10
P=26.2 units
It's the first one, an algebraic expression contains variables
Answer:
<h2>The answer is 5 units</h2>
Step-by-step explanation:
The distance between two points can be found by using the formula
where
(x1 , y1) and (x2 , y2) are the points
From the question
The points are (9,-7) and (5, -4)
The distance between them is
We have the final answer as
<h3>5 units</h3>
Hope this helps you
Answer:
3.8
Step-by-step explanation:
3(-7.9)-5(-5.5)
3.8
Hope this helps!
