Answer:
Option B is correct.
Angle DAC is congruent to angle DAB
Step-by-step explanation:
Given: Segment AC is congruent to segment AB.
In ΔABD and ΔACD
[Given]
[Congruent sides have the same length]
AB = AC [Side]
AD = AD [Common side]
[Angle]
Side Angle Side(SAS) Postulate states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.
Then by SAS,

By CPCT [Corresponding Parts of congruent Triangles are congruent]
then;

therefore, only statement which is used to prove that angle ABD is congruent to angle ACD is: Angle DAC is congruent to DAB
Answer:
122.30 cm²
Step-by-step explanation:
The figure is a triangular prism.
Formula for calculating surface area of a triangular prism = bh + L(S1 + S2 + S3)
Where,
b = 11 cm
h = 4.3 cm
S1 = 8 cm
S2 = 6 cm
S3 = 11 cm
L = 3 cm
Surface area = 11*4.3 + 3(8 + 6 + 11)
= 47.3 + 3(25)
= 122.3 cm²
<span> Slope = 1.000/2.000 = 0.500 x-intercept = 5/-1 = -5.00000<span> y-intercept = 5/2 = 2.50000</span></span>
Answer:
P=0.147
Step-by-step explanation:
As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2
We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.
We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) . To find the required probability 3 mentioned probabilitie have to be summarized.
So P(9/16 )= C16 9 * P(good brakes)^9*Q(bad brakes)^7
P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02
P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007
P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12
P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147