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2 years ago

Can someone help me and solve the following equation showing work please? thank you!

Mathematics

1 answer:

dsp732 years ago

3 0

The angle made by an arc at the centre of the circle is double the angle made by the same arc at any point on the circle. The measure of the angle θ will be 45°.

<h3>What are an arc and subtended angle theorem?</h3>

According to the arc and subtended angle theorem, The angle made by an arc at the centre of the circle is double the angle made by the same arc at any point on the circle.

The angle made by an arc at the centre of the circle is double the angle made by the same arc at any point on the circle. Therefore, the measure of the angle θ will be half the measure of the ∠P.

As it can be observed the measure of the angle ∠P is 90°, therefore, the measure of the angle θ can be written as,

∠P = 2 × ∠θ

90° = 2 × ∠θ

∠θ = 45°

Hence, the measure of the angle θ will be 45°.

Learn more about Arc and Subtended angle Theorem:

brainly.com/question/1364009

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HELP!!!!!

Sonja [21]

First off, let's convert the decimal to a fraction, notice, we have two decimals, so we'll use in the denominator, a 1 with two zeros then, two decimals, two zeros, thus $\bf 1.\underline{75}\implies \cfrac{175}{1\underline{00}}\implies \cfrac{7}{4}\implies \stackrel{ratio}{7:4}$

now, we know then the ratio dimensions for the new photograph,

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\cfrac{7}{4}\implies \cfrac{4+3}{4}\implies \cfrac{4}{4}+\cfrac{3}{4}\implies 1+\boxed{\cfrac{3}{4}}\impliedby \textit{perimeter is }\frac{3}{4}\textit{ larger}
\\\\\\
\stackrel{areas'~ratio}{\cfrac{s^2}{s^2}}\implies \cfrac{3^2}{4^2}\implies \cfrac{9}{16}\impliedby \textit{area is }\frac{9}{16}\textit{ larger than original}$

6 0

3 years ago

You need 200 mL of a 10% alcohol solution. On hand, you have a 25% alcohol mixture. How much of the 25%

Anastasy [175]

so yull do math I'm guna do different number just plug these in for.your numbers 225/(375+x)=25

cross multiply land solve900-375 x=525 then cheak

225/(375+525) = .25

4 0

3 years ago

Micah is writing a function that models the height a dolphin reaches when it propels itself from underwater to the surface, leap

stepladder [879]

Answer:

The dolphin will be above the surface of the water for 2 seconds.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

The height of the dolphin after t seconds is given by:

$h(t) = -16t^2 + 96t - 128$

According to Micha's model, how long will the dolphin be above the surface of the water?

It stays above the surface of the water between the first and the second root. Initially, it is below water, when the first time for which $h(t) = 0$ it crosses the surface upwards, and then the second time for which $h(t) = 0$ it crosses the surface downwards.