1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natka813 [3]
3 years ago
14

Is the number of calories you have burned since midnight at any time during the say a function\?

Mathematics
1 answer:
statuscvo [17]3 years ago
8 0
<span>Yes, this would be considered a function of time elapsed. To be a function, there needs to be exactly a one-to-one relationship between the variables. At any one time (elapsed since midnight), there is exactly one value for the number of calories burned.</span>
You might be interested in
Which function is equivalent to y = 3(x + 2)2 + 7?
Tems11 [23]

Answer:

The answer is D

Step-by-step explanation:

I wish i can explan but i got to go, piece

7 0
2 years ago
What is the correct simplified version of the expression 32x + 8 - 34x?
MakcuM [25]

Answer:

  -2x +8

Step-by-step explanation:

The terms involving x are "like" terms, so their coefficients are added when the terms are combined.

  = 32x -34x +8

  = (32 -34)x +8 . . . . . x is factored out according to the distributive property

  = -2x +8

5 0
3 years ago
Which is the approximate solution to the system y = 0.5x + 3.5 and y = − 2/3 x + 1/3 shown on the graph? (–2.7, 2.1) (–2.1, 2.7)
AlekseyPX

Answer:

The approximate solution to the system is (-2.7, 2.1).

Step-by-step explanation:

To solve the system of equations \begin{bmatrix}y=0.5x+3.5\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix} you must:

\mathrm{Rationalize\:equations}\\\\\begin{bmatrix}y=\left(\frac{1}{2}\right)x+\left(\frac{7}{2}\right)\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}

\mathrm{Subsititute\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\begin{bmatrix}-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\end{bmatrix}

\mathrm{Isolate}\:x\:\mathrm{for}\:-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\\\\-\frac{2}{3}x=\frac{19}{6}+\frac{1}{2}x\\\\-\frac{7}{6}x=\frac{19}{6}\\\\6\left(-\frac{7}{6}x\right)=\frac{19\cdot \:6}{6}\\\\-7x=19\\\\x=-\frac{19}{7}\approx-2.7

\mathrm{For\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\mathrm{Subsititute\:}x=-\frac{19}{7}\\\\y=-\frac{2}{3}\left(-\frac{19}{7}\right)+\frac{1}{3}\\\\y=\frac{15}{7}\approx 2.1

The approximate solutions to the system of equations are:

x=-2.7 ,\:y=2.1

5 0
3 years ago
Read 2 more answers
Please do this question
crimeas [40]
It would be 16 more 6th graders that are not in either band or orchestra.
  15 6th Graders in band
  9 6th Graders in both classes
+18 6th Graders in orchestra
-----
42 6th Graders in either class

  100 6th Graders in total
 -42 6th Graders in either class
-------
58 6th Graders in neither class
 58-42= 16 more 6th Graders that are not in either class
You're welcome :)

7 0
3 years ago
8(8p+8)=640 solve <br> Answer ASAP please
Ede4ka [16]

Answer:

p = 9

Step-by-step explanation:

8(8p + 8) = 640

use the dist property

64p + 64 = 640

<u>         -64      -64</u>

64p = 576

divide by 64

p = 9

6 0
3 years ago
Read 2 more answers
Other questions:
  • Simplify the expression:
    14·1 answer
  • When calculated, the two differences given below are equal.
    9·1 answer
  • Robin can mow a lawn in 3 hours, while Brady can mow the same lawn in 4 hours. How many hours would it take for them to mow the
    7·1 answer
  • Is the relationship shown by the data linear? If so, model the data with an equation.
    11·1 answer
  • The side lengths of a triangle are 40, 50, and 80. What are the angle measures in the triangle?
    15·1 answer
  • Which point on the number line represents -1/3?<br> A<br> В<br> С<br> D
    9·2 answers
  • -x+ x² - 6 what is the answer ​
    12·2 answers
  • Help needed
    5·1 answer
  • Write 7x7 in exponential form
    15·1 answer
  • A rectangle has and area of 55 Square inches and a length of 5 inches what is the width
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!