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Blizzard [7]
3 years ago
15

a box contains 5 plain pencils and 5 pens. a second box contains 7 color pencils and 5 crayons. one item from each box is chosen

at random. what is the probability that a pen from the first box and a crayon from the second box are selected?
Mathematics
1 answer:
Ket [755]3 years ago
5 0
First box: \dfrac{pen}{total}=\dfrac{5}{10}=\dfrac{1}{2}

Second box: \dfrac{crayon}{total}=\dfrac{5}{12}

Multiply them:

\dfrac{1}{2}*\dfrac{5}{12}=\dfrac{5}{24}

The probabilityis \dfrac{5}{24}
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Part (a)

<h3>Answer: x^3 + 12x^2 + 47x + 60</h3>

--------------------------

Work Shown:

Let's say we have

  • L = length = x+5
  • W = width = x+4
  • H = height = x+3

To find the volume of the block, we multiply the length width and height.

So,

volume = (length)*(width)*(height)

V = L*W*H

V = LW*(x+3) .... replace H with (x+3)

V = LW*x + LW*3 .... distribute

V = Lx*(W) + 3L*(W)

V = Lx(x+4) + 3L(x+4) .... replace W with x+4

V = Lx^2 + 4Lx + 3Lx + 12L .... distribute

V = Lx^2 + 7Lx + 12L

V = x^2*(L) + 7x*(L) + 12*(L)

V = x^2*(x+5) + 7x*(x+5) + 12*(x+5) .... replace L with x+5

V = x^3 + 5x^2 + 7x^2 + 35x + 12x + 60 .... distribute

V = x^3 + 12x^2 + 47x + 60

x^3 + 12x^2 + 47x + 60 is the polynomial in standard form that represents the volume of the block.

=======================================================

Part (b)

<h3>Answer: 336 cubic feet</h3>

--------------------------

Work Shown:

We can plug x = 3 into the polynomial we found

V = x^3 + 12x^2 + 47x + 60

V = (3)^3 + 12(3)^2 + 47(3) + 60

V = 27 + 12(9) + 47(3) + 60

V = 27 + 108 + 141 + 60

V = 336

Or we could find the volume like this

V = L*W*H

V = (x+5)*(x+4)*(x+3)

V = (3+5)*(3+4)*(3+3)

V = (8)*(7)*(6)

V = 336

Either way, we get the same volume of 336 cubic feet.

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