All categories

2 years ago

Find the surface area

Mathematics

2 answers:

steposvetlana [31]2 years ago

6 0

Answer:

should be 872 in^2

Step-by-step explanation:

Arada [10]2 years ago

6 0

Answer:

Area = 872

Step-by-step explanation:

Formula for the surface area of a rectangular prism is

A=2(wl+hl+hw)

Plug in

A =2·(8·17+12·17+12·8)=872

You might be interested in

7x-5=8(x+3) solve for x

Harlamova29_29 [7]

Answer:

The value of x is -29.

Step-by-step explanation:

We are given an algebraic equation and have one goal: solve for x. We can use simplifying techniques as well as addition and subtraction to solve this equation.

$\text{7x - 5 = 8(x + 3) \ \ \ Distribute the 8 throughout the parentheses.}\\\text{7x - 5 = 8x + 24 \ \ \ \ Subtract 7x from both sides.}\\\text{-5 = x + 24 \ \ \ \ \ \ \ \ \ \ Flip the equation.}\\\text{x + 24 = -5 \ \ \ \ \ \ \ \ \ \ Subtract 24 from both sides.}\\\small\boxed{\bold{{x = -29}}}$

Now that we have solved for x, we can plug in -29 to see if we get a true statement.

$\text{7(-29) - 5 = 8(-29 + 3)}\\\text{-203 - 5 = -232 + 24}\\\text{-208 = -208} \ \checkmark$

Because we ended up with a true statement, we have determined that the value of x is -29.

6 0

3 years ago

A lake polluted by bacteria is treated with an antibacterial chemical. Aftertdays, thenumber N of bacteria per milliliter of wat

jeyben [28]

Answer:

N(1)=50 is a minimum

N(15)=4391.7 is a maximum

Step-by-step explanation:

<u>Extrema values of functions </u>

If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.

We are given a function (corrected)

$N(t) = 20(t^2-lnt^2)+ 30$

$N(t) = 20(t^2-2lnt)+ 30$

(a)

First, we take its derivative

$N'(t) = 20(2t-\frac{2}{t})$

Solve N'(t)=0

$20(2t-\frac{2}{t})=0$

Simplifying

$2t^2-2=0$

Solving for t

$t=1\ ,t=-1$

Only t=1 belongs to the valid interval $1\leqslant t\leqslant 15$

Taking the second derivative

$N''(t) = 20(2+\frac{2}{t^2})$

Which is always positive, so t=1 is a minimum

(b)

$N(1)=20(1^2-2ln1)+ 30$

N(1)=50 is a minimum

(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15

(d)

$N(15)=20(15^2-2ln15)+ 30$

N(15)=4391.7 is a maximum

7 0

3 years ago

Which statement s true about this right triangle?

12345 [234]

Where is the picture ?? I don’t understand ok

8 0

2 years ago

B 5 3 a 4 What is the length of the hypotenuse of this triangle? 3 units 5 units 4 units

Lunna [17]

Answer:

5 units

Step-by-step explanation:

The hypotenuse is always the longest segment on a triangle. If the lengths of the sides of this triangle are 3 units, 4 units, and 5 units, the hypotenuse will be 5 units. You can use the pythagorean theorem to check.

a^2+b^2=c^2

If you substitute the variable with the lengths of the legs in ascending order, you will get 3^2+4^2=5^2. Simplifying the equation, you will get 9+16=25, or 25=25. Thus, proving the equation.

Hope this helped! :)

6 0

3 years ago

I need help please ?!!

melomori [17]

the answer is b because the answer for both of them is -39. you might also want to look into the sign rules in algebra bb :)

3 0

3 years ago