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Anon25 [30]
3 years ago
7

WILL GIVE BRAINLIST On a coordinate plane, 2 quadrilaterals are shown. The first figure has points A (negative 2, 1), B (negativ

e 4, 1), C (negative 4, 5), and D (negative 2, 4). Figure 2 has points A prime (2, 1), B prime (4, 1), C prime (4, 5), and D prime (2, 4). What is the rule for the reflection? rx-axis(x, y) → (–x, y) ry-axis(x, y) → (–x, y) rx-axis(x, y) → (x, –y) ry-axis(x, y) → (x, –y)
Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0
The rule of reflection is ry-axis (x , y) → (-x , y)
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Answer:

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Step-by-step explanation:

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Natasha2012 [34]

Answer:

m∠B = 70.0° (nearest tenth)

Step-by-step explanation:

<u>Sine Rule for Angles</u>

\sf \dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}

(where A, B and C are the angles and a, b and c are the sides opposite the angles)

Given:

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Substituting the given values into the formula to find m∠C:

\implies \sf \dfrac{\sin 40^{\circ}}{13}=\dfrac{\sin C}{19}

\implies \sf \sin C=\dfrac{19\sin 40^{\circ}}{13}

\implies \sf C=\sin^{-1}\left(\dfrac{19\sin 40^{\circ}}{13}\right)

\implies \sf m \angle C=69.96086904^{\circ}

Interior angles of a triangle sum to 180°

\implies \sf m \angle A+ m \angle B+m \angle C=180^{\circ}

\implies \sf 40^{\circ} + m \angle B+69.960...^{\circ}=180^{\circ}

\implies \sf m \angle B=70.03913...^{\circ}

Therefore, m∠B = 70.0° (nearest tenth)

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