Well to solve this problem first you need to know the multiples of 4,6, and 8. Can you list them for me?
Then you find a number that is a multiple of all the numbers 4,6, and 8 that is in between 67 and 113.
Answer:
i believe so
Step-by-step explanation:
Answer:
y^3 - 9y^2 + 26y - 29
Step-by-step explanation:
y - 4[y - 3(y - 2)] - 5
I'm going to separate it into parts
(y - 3)(y - 2)
y^2 - 5y + 6
(y - 4)(y^2 - 5y + 6)
y^3 - 5y^2 + 6y - 4y^2 + 20y - 24
y^3 - 9y^2 + 26y - 24
y^3 - 9y^2 + 26y - 24 - 5
y^3 - 9y^2 + 26y - 29
Solve your system of equations.
2x+y=1;4x+2y=−1
Solve 2x+y=1 for y:
2x+y+−2x=1+−2x(Add -2x to both sides)
y=−2x+1
Substitute (−2x+1) for y in 4x+2y=−1:
4x+2y=−1
4x+2(−2x+1)=−1
2=−1(Simplify both sides of the equation)
2+−2=−1+−2(Add -2 to both sides)
0=−3
Answer: No solution. C)
