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Vladimir [108]
1 year ago
14

Javon is in a 30% tax bracket for his federal income tax. If the amount of money that he paid for federal income tax was $21,000

, what was his taxable income?
Mathematics
1 answer:
vekshin11 year ago
6 0

Answer:

Step-by-step explanation:

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What is the product of the polynomials below? (6x3 + 3x)(x2 + 4)
shutvik [7]
6x5+24x3+3x3+12x ------> Simplify by adding like terms

6x5 + 27x3 + 12x
5 0
3 years ago
What is the solution to 3/8 x 1/8?
babymother [125]

Answer:

3/64

Step-by-step explanation:

Multiply straight across the numerators and then denominators

  3              1                3

-------  X  ----------  =  ---------

  8              8              64

4 0
3 years ago
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F(x)=3x^3-4x^2+6x and g(x)=5x^3+2x^2-3x what is f(x)-g(x)
mrs_skeptik [129]
F(x) - g(x) = -2x^3 - 6x^2 + 9x
7 0
3 years ago
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A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin
Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

P(\dfrac{X}{Y}) = 60\% = 0.6

P(\dfrac{X}{Y'}) = 0.01\% = 0.0001

P(Y) = 0.01

Thus, P(Y') \ will\ be = 1 - P(Y)

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

P(YX) = P(\dfrac{X}{Y}) \ P(Y)

P(YX) =0.6 \times 0.01

P(YX) =0.006

The probabilities of not involved in cheating & the evidence are present is:

P(Y'X) = P(Y')  \times P(\dfrac{X}{Y'})

P(Y'X) = 0.99  \times 0.0001 \\ \\  P(Y'X) = 0.000099

(b)

The required probability that the evidence is present is:

P(YX  or Y'X) = 0.006 + 0.000099

P(YX  or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}

P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}

P(\dfrac{Y}{X}) = 0.9838

5 0
3 years ago
The side of a square is 11.2 cm. what is the length of the diagonal
Snowcat [4.5K]
You can work out the diagonal by using Pythagoras theorem. (a^2 = b^2 + c^2)

As it is a square, all 4 sides are the same so it would be:
11.2^2 + 11.2^2 = diagonal^2
250.88 = diagonal^2
Square root both sides to get what the diagonal is equal to.
diagonal is 15.8 cm
3 0
3 years ago
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