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kap26 [50]
2 years ago
8

What is the change in entropy of 250 g of steam at 100 ∘c when it is condensed to water at 100 ∘c?

Chemistry
1 answer:
Veronika [31]2 years ago
4 0

Entropy change is the randomness of the thermodynamic system. The change in the entropy when the water is condensed is 1573 J/K.

<h3>What is the entropy change?</h3>

An entropy change is a product of mass and the ratio of the enthalpy of vaporization to the temperature.

Given,

Enthalpy of vapourization =  2257 J/gK

The temperature in kelvin = 373 k

The change in entropy is calculated as:

\begin{aligned} \rm \Delta S &= \rm m (\dfrac{\Delta H_{vap}}{T})\\\\&= 260 (\dfrac{2257}{373})\\\\&= 1573.24\;\rm J/K\end{aligned}

Therefore, the change in entropy is 1574 J/K.

Learn more about entropy here:

brainly.com/question/14798359

#SPJ4

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Describing physical and chemical changes:
svetoff [14.1K]
Physical: The chemist could try to bend it to find out how malleable it is. He could also try to pull it into wires to find out how ductile it is.

Chemical: The chemist could put the metal into contact with other substances to get an idea of how reactive it is, and he could try to burn it and find out how flammable it is.
8 0
4 years ago
How many grams of Na2SO4 should be weighed out to prepare 0.5L of a 0.100M solution?​
Nezavi [6.7K]

Answer:

7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100 M solution.

Explanation:

First of all the molecular weight of Na2SO4 is 142.08 gram.Now we all know that if the molecular weight of a compound is dissolved in 1000ml or 1 litee of water then the strength of that solution becomes 1 M.

    According to the given question we have to prepare 0.100 M solution

1000 ml of solution contain 142.08×0.1= 14.208 gram Na2SO4

1    ml of solution contain     14.208÷1000= 0.014 gram

0.5L or 500ml of solution contain 0.014×500= 7gram Na2SO4.

 So it can be stated that 7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100M solution.

     

3 0
3 years ago
. How many grams of water would require 4400 joules
Alja [10]

Answer:

The specific heat of water is 4.18 J/g C.

Explanation:

q

=

m

C

s

Δ

T

Never forget that!

2200

=

m

⋅

4.18

J

g

⋅

°

C

⋅

66

°

C

∴

m

≈

8.0

g

5 0
3 years ago
Carbon dioxide gas occupies a volume of 20.0 L at 308K and 2.30 atm. What volume would it occupy at 416 K and 5.40 atm?
Brrunno [24]

Answer : The final volume of gas is, 11.5 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 2.30 atm

P_2 = final pressure of gas = 5.40 atm

V_1 = initial volume of gas = 20.0 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 308 K

T_2 = final temperature of gas = 416 K

Now put all the given values in the above equation, we get:

\frac{2.30atm\times 20.0L}{308K}=\frac{5.40atm\times V_2}{416K}

V_2=11.5L

Therefore, the final volume of gas is, 11.5 L

7 0
3 years ago
Read 2 more answers
Which of the following are likely to form an ionic bond
sattari [20]

Answer:

No question is posted.

But Ionic bond is mostly between metals live Na, K, Ca, Mg and strong non metals like Cl, O, F

Explanation:

3 0
3 years ago
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