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Advocard [28]
2 years ago
12

Lord kelvin described the concept of absolute zero temperature and the laws relating the change in thermal energy during chemica

l reactions. whaty type of chemist would be be considered todayh
Chemistry
1 answer:
kondaur [170]2 years ago
6 0
Lord Kelvin, were he alive today, would be considered a Thermochemist. Thermochemistry is interested in the role of heat in chemical reactions. This includes the role of heat both as a biproduct of chemical reactions and a facilitator.

Kelvin's description of absolute zero is an important concept in thermochemistry. At absolute zero, there is no movement of molecules, and no energy available facilitate chemical reactions. 
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Binary compounds of alkali metals and hydrogen react with water to liberate hydrogen gas. The hydrogen gas from the reaction of
DanielleElmas [232]

Answer: The mass of H_{2} liberated is 0.0383 g and the mass of NaH that reacted 0.455 g.

Explanation:

The given data is as follows.

       Volume = 0.501 L,

 Temperature of gas = 35^{o}C = (35 + 273) K = 308 K,

 Total pressure = 760 mm Hg

  Vapor pressure of water at 35^{o}C = 422 mm Hg

  Partial pressure of H_{2} = (760 - 422) mm Hg

                                     = 717.8 mm Hg

The chemical equation is as follows.

       NaH + H_{2}O \rightarrow NaOH + H_{2}

Using ideal gas equation, we will find the moles of hydrogen gas as follows.

             PV = nRT

         n = \frac{PV}{RT}

As we know,

               1 atm = 760 mm Hg

      717.8 mm Hg = 717.8 \times \frac{1 atm}{760 mm Hg}    

                             = 0.944 atm

Putting the given values into the above formula we will calculate the number of moles as follows.

                    n = \frac{PV}{RT}

                       = \frac{0.944 atm \times 0.510 L}{0.08206 Latm/mol K \times 308 K}

                       = 0.0190 moles

Now, we will find the mass of H_{2} as follows.

       Mass = Moles × Molar mass

                 = 0.0190 moles × 2.01588 g/mol

                 = 0.0383 g

Therefore, mass of hydrogen is 0.0383 g.

As the ratio between H_{2} and NaH is 1:1. So, we will calculate the moles of NaH as follows.

             Mass = Moles × Molar mass

                       = 0.0190 moles × 23.99771 g/mol

                       = 0.455 g

Therefore, mass of NaH is 0.455 g.

6 0
2 years ago
How many periods does the modern periodic table have?
dusya [7]
There are 7 periods in the modern periodic table

8 0
3 years ago
 
Katyanochek1 [597]

Answer:

The answer to your question is     V2 = 4.97 l

Explanation:

Data

Volume 1 = V1 = 4.40 L                    Volume 2 =

Temperature 1 = T1 = 19°C               Temperature 2 = T2 = 37°C

Pressure 1 = P1 = 783 mmHg           Pressure 2 = 735 mmHg

Process

1.- Convert temperature to °K

T1 = 19 + 273 = 292°K

T2 = 37 + 273 = 310°K

2.- Use the combined gas law to solve this problem

                  P1V1/T1  = P2V2/T2

-Solve for V2

                  V2 = P1V1T2 / T1P2

-Substitution

                  V2 = (783 x 4.40 x 310) / (292 x 735)

-Simplification

                 V2 = 1068012 / 214620

-Result

                 V2 = 4.97 l

6 0
3 years ago
How can radioactivity be used to help find the age of an object ?
gogolik [260]

Hope this answers your question Mariaduong159

Radiometric Dating. It's used to find the dates of ricks and other objects based on what the known decay rate of radioactive isotopes. Different forms of this method can also estimate the age of natural and man-made materials.

8 0
3 years ago
What is the pH of a solution of RbOH with a concentration of 0.86 M? Answer to 2 decimal places
lubasha [3.4K]

Answer:The pH of the solution is given by pH=−log([H3O+])

Explanation:so you can't use

pH

=

−

log

(

0.150

)

because that's the concentration of the hydroxide anions,

OH

−

, not of the hydronium cations,

H

3

O

+

. In essence, you calculated the

pOH

of the solution, not its

pH

.

Sodium hydroxide is a strong base, which means that it dissociates completely in aqueous solution to produce hydroxide anions in a

1

:

1

mole ratio.

NaOH

(

a

q

)

→

Na

+

(

a

q

)

+

OH

−

(

a

q

)

So your solution has

[

OH

−

]

=

[

NaOH

]

=

0.150 M

Now, the

pOH

of the solution can be calculated by using

pOH

=

−

log

(

[

OH

−

]

)

−−−−−−−−−−−−−−−−−−−−

In your case, you have

pOH

=

−

log

(

0.150

)

=

0.824

Now, an aqueous solution at

25

∘

C

has

pH + pOH

=

14

−−−−−−−−−−−−−−so you can't use

pH

=

−

log

(

0.150

)

because that's the concentration of the hydroxide anions,

OH

−

, not of the hydronium cations,

H

3

O

+

. In essence, you calculated the

pOH

of the solution, not its

pH

.

Sodium hydroxide is a strong base, which means that it dissociates completely in aqueous solution to produce hydroxide anions in a

1

:

1

mole ratio.

NaOH

(

a

q

)

→

Na

+

(

a

q

)

+

OH

−

(

a

q

)

So your solution has

[

OH

−

]

=

[

NaOH

]

=

0.150 M

Now, the

pOH

of the solution can be calculated by using

pOH

=

−

log

(

[

OH

−

]

)

−−−−−−−−−−−−−−−−−−−−

In your case, you have

pOH

=

−

log

(

0.150

)

=

0.824

Now, an aqueous solution at

25

∘

C

has

pH + pOH

=

14

−−−−−−−−−−−−−−

3 0
2 years ago
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