Answer:
volume = 13097674418.528dm³
Explanation:
n = (3.52)*10^32/(6.02)*10^23)
n = (584717607.97)
n = volume /molar volume
molar volume at stp = 22.4dm³
volume= 584717607.97 x 22.4
volume = 13097674418.528dm³
122 moles of Methane to liters is 2734.5
Answer:
T2 = 36.38°C
Explanation:
Given data:
Mass of water = 75 g
Initial temperature = 30 °C
Final temperature = ?
Heat absorbed = 2000 J
Solution:
Specific heat capacity of water is 4.18 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = Final temperature - initial temperature
2000 J = 75 g×4.18 J/g.°C × T2- T1
2000 J = 313.5 J/°C × T2- T1
2000 J = 313.5 J/°C × T2 - 30 °C
2000 J / 313.5 J/°C = T2 - 30 °C
6.38 °C = T2 - 30 °C
T2 = 6.38 °C + 30°C
T2 = 36.38°C
Answer:
15.5 moles
Explanation:
Applying,
PV = nRT.................. Equation 1
Where P = pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.
Make n the subject of the equation
n = PV/RT............... Equation 2
From the question,
Given: P = 0.899 atm, V = 425 L, T = 24 °C = (273+24) K = 297 K.
Constant: R = 0.083 L.atm/K.mol
Substitute these values into equation 2
n = (0.899×425)/(297×0.083)
n = 15.5 moles
