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Zolol [24]
2 years ago
10

Can someone please help me with this

Mathematics
1 answer:
fenix001 [56]2 years ago
3 0

Answer:

d = \sqrt{109}

Step-by-step explanation:

Use the <u>distance formula</u>.

\text{The distance between two points } (x_1, y_1) \text{ and } (x_2, y_2) \text{ is given by the formula:}\\d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Your points are (-4, 11) and (6, 8).

d = \sqrt{(-4 - 6)^2 + (11 - 8)^2}\\\\d = \sqrt{(-10)^2 + (3)^2}\\\\d = \sqrt{100 + 9}\\\\d = \sqrt{109}

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NemiM [27]

Answer:

0033

Step-by-step explanation:

.033 of a whole number so its .033

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3 years ago
PLS HELP ME FOR 4, 5, and 6 ASAP GUYSSS ( SHOW WORK!!) + lots of POINTS!!
Evgesh-ka [11]
4. D
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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
I need the solution
shutvik [7]

\dfrac{8c^3}{6(c+d)}\div\dfrac{2c^2}{3c+3d}=\dfrac{4c^3}{3(c+d)}\div\dfrac{2c^2}{3(c+d)}\\\\=\dfrac{4c^3}{3(c+d)}\cdot\dfrac{3(c+d)}{2c^2}=\dfrac{4c^3}{2c^2}=2c

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S_A_V [24]

Answer:

1. 30

2. x<-72

3. 7b=63

4. x=3.2

5. 1/10

Step-by-step explanation:

1. Substitute a for 10

2(150/10)

2*15

30

2. Think of it like a normal equation

x/4<-18

x<-18*4

x<-72

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4. 2.5x=8

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3 years ago
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