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shepuryov [24]
2 years ago
10

Find the constants a and b such that the function is continuous on the entire real line

Mathematics
1 answer:
Nezavi [6.7K]2 years ago
4 0

Answer:

a=-2, b=1.

Step-by-step explanation:

1) according to the condition it is required to find the equation of line, which passes through points A(-3;7) and B(4;-7);

2) the equation of this line can be made up using the formula:

\frac{x-X_A}{X_B-X_A} =\frac{y-Y_A}{Y_B-Y_A};

\frac{x+3}{4+3} =\frac{y-7}{-7-7} ; \ < = > \ x+3=\frac{y-7}{-2}.

3) if to re-write the last equation, then

y=-2x+1;

4) finally, a= -2; b=1.

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Which 2 values of x are roots of the polynomial below?
Alexxx [7]

Given:

The given polynomial is:

f(x)= 3x^{2}-3x+1

To find the roots of the given polynomial.

To find the roots we have to take f(x) = 0

So,

3x^{2} -3x+1 = 0

Formula

By quadratic formula, the root of the equation ax^{2} +bx+c = 0 is,

x = \frac{-b+\sqrt{b^{2}-4ac } }{2a} and \frac{-b-\sqrt{b^{2} -4ac} }{2a}

Now,

Putting, a=3, b=-3, c=1 we get,

x = \frac{3+\sqrt{3^{2}-4(3)(1) } }{(2)(3)} and \frac{3-\sqrt{3^{2}-4(3)(1) } }{(2)(3)}

x = \frac{3+\sqrt{-3} }{6} and x=\frac{3-\sqrt{-3} }{6}

Hence,

The values of the roots of the given polynomial arex=\frac{3+\sqrt{-3} }{6} and x=\frac{3-\sqrt{-3} }{6}

Hence, Option A and F are the correct answer.

5 0
3 years ago
If 10^y=y^10, then what is y?
Andrew [12]

Answer:

1

Step-by-step explanation:

10 to the power of 1 is 1, 1 to the power of 10 is still 1

8 0
3 years ago
A. True/False
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Answer:

True

Step-by-step explanation:

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The ratio of boys to girls in the Grade 3 classes at Domino Primary school
olga_2 [115]

Answer:

28 learners

Step-by-step explanation:

Boys : Girls

3 : 4

Since there are 12 boys and 3 units of them...

3 units = 12

1 unit = 12 ÷ 3 = 4

Girls =

4 units = 4 x 4 = 16

Total number of girls and boys: 12 + 16 = 28

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Answer:

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Step-by-step explanation:

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