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rosijanka [135]
3 years ago
13

If two opposite sides of a quadrilateral are perpendicular and congruent, then the quadrilateral is a parallelogram.

Mathematics
2 answers:
romanna [79]3 years ago
6 0
B. False.  hope I could help:)
Semenov [28]3 years ago
3 0

FALSEEEEEEEEEEEEEEEEEEEEEE!

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I need help asapp!!!!!!!
labwork [276]

Answer:

Step-by-step explanation:

As per midsegment theorem of a trapezoid,

Segment joining the midpoints of the legs of the of the trapezoid is parallel to the bases and measure half of their sum.

Length of midsegment = \frac{1}{2}(b_1+b_2)

3). MN = \frac{1}{2}(18+10)

           = 14

4). MN = \frac{1}{2}(57+76)

           = 66.5

5). MN = \frac{1}{2}(AB+DC)

    7 = \frac{1}{2}(AB+10)

    14 = AB + 10

    AB = 14 - 10

    AB = 4

6). 15 = \frac{1}{2}[(3x+2)+(2x-2)]

    30 = 5x

     x = 6

4 0
2 years ago
Martina chose a random sample of 10 bags of candy from two different Brands, A and B. All bags in the sample are the same size.
Alborosie
I found the dot plots that accompanies this problem.

Based on the plots, the <span>statement that gives is a valid comparison of the number of candies in the bags of the two Brands is:

</span><span>B. The number of candies in the bags from Brand B is greater and less consistent than the number of candies in the bags from Brand A.

Dots in Brand B are scattered and whereas dots in Brand A are not and they are more concentrated between 52 to 55 range. </span>

7 0
2 years ago
Find the slope of the line through each pair of points (19,9),(15,-3)
stepan [7]
Slope (y2-y1)/(x2-x1)
(-3-9)/(15-19) = -12/-4 = 3
The slope is 3
4 0
3 years ago
HELP ME PLEASE ASAP!​
Viktor [21]

Answer:

second option

Step-by-step explanation:

Pythagoras for right-angled triangles :

c² = a² + b²

c is the Hypotenuse, the line opposite of the 90 degree angle.

a and b are the other 2 sides.

the distance between 2 points is the Hypotenuse of a right-angled triangle of the coordinate differences in x and y.

so, we have (-2, -3) and (3, 2)

distance² = (x1 - x2)² + (y1 - y2)² = (-2 - 3)² + (-3 - 2)² =

= (-5)² + (-5)² = 25 + 25 = 2×25 = 50

distance = sqrt(50) = sqrt(2×25) = 5×sqrt(2)

7 0
2 years ago
See attached file, please help
Luba_88 [7]
System of Equations:
{-2x+2
{-1/3x-3

I used y=mx+b to find the equations
4 0
3 years ago
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