A]
D=R×t
d=5.8r
d2=5.1(r+7)
0.7r=35.7
r=51 mi/hr
thus the average speed on the outbound trip would be:
51+7=58 mi/hr
b]
let speed of fishing boat=x km/h
speed of cruise ship=(x+12.5) km/h
distance traveled by fishing boat=11.5×x=11.5x km
distance traveled by cruise ship=(x+12.5)×11=(11x+137.5) km
Total distance covered by the ships:
11.5x+11x+137.5=322
22.5x=322-137.5
22.5x=184.5
thus
x=184.5/22.5
x=8.2 km/h
The speed of fishing boat is 8.2 km/hr
Answer:
Salena's got to the library first
Step-by-step explanation:
12½ miles = 25/2 miles
2½ miles = 5/2 miles
5¾ miles = 23/4 miles
114 miles = 114 miles
Salena's time of arrival =
if 5/2 miles : 5 minutes
then 25/2 miles : ?
25/2 ÷ 5/2. × 5
25/2 × 2/5 × 5
25 minutes
Justin 's time of arrival=
if 23/4 miles : 12 minutes
25/2 miles : ?
25/2 ÷ 23/4 ×12
25/2 × 4/23 ×12
26 minutes approximately
Brandon 's time of arrival=
if 114 miles : 258 minutes
25/2 miles : ?
25/2 ÷114 ×258
25/2 × 1/114×258
25 × 1/57 × 258
113 minutes approximately
A since 19 x 29= 551 and 551/375 is around 1.5
Answer:
A
Step-by-step explanation: