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pashok25 [27]
3 years ago
5

HELP ILL MARK BRAINLIEST

Mathematics
1 answer:
bonufazy [111]3 years ago
5 0

Answer:

-5c

Step-by-step explanation:

c+c-7c > 2c-7c = -5c

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I do not know #5 plz help
aliya0001 [1]

It's saying one company had a profit of ~ $8M and another had a profit of ~ $8.5M+. Which company had the greater profit?

The answer is the one with the bigger number; Coyle Company

3 0
3 years ago
Solve for S.<br> 4s-28=4
lina2011 [118]

Answer: s = 8

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.
Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{1599\text{ years}}

k=4.33\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 1000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=5.19g

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 10000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=0.105g

Thus, the amount after 10000 years will be, 0.105 grams.

4 0
3 years ago
I need help with the first two
mel-nik [20]
The work and answer provided are correct, the simpler way of doing it is

1)
1/6 page written in 1/12 of a minute
to write a full page, you would need to write 1/6, 6 times
so,
\frac{1}{6} \time 6 = 1
and
\frac{1}{12} \times 6 = \frac{6}{12} = \frac{1}{2}

so it takes 1/2 of a minute to write a full page, there are 60 seconds in a minute, 1/2 of 60 seconds is 30 seconds

same process works for question 2(use 3 instead of 6 though)
6 0
3 years ago
Q7.
VLD [36.1K]

Answer:

10

Step-by-step explanation:

Let c = sum of ages of all children.

mean age of all children = c/15 = 7

c = 15 * 7 = 105

The sum of the ages of all children is 105.

Let b = sum of ages of the 9 boys.

mean age of boys = b/9 = 5

b = 9 * 5 = 45

The sum of the ages of the boys is 45.

The sum of the ages of the girls is c - b.

c - b = 105 - 45 = 60

The number of girls is 15 - 9 = 6

mean age of girls = (sum of ages of the girls)/(number of girls) =

= 60/6 = 10

3 0
3 years ago
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