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Naddika [18.5K]
3 years ago
8

The width of a rectangle is 3 meters less than the length period the perimeter is 14 meters. Find the width

Mathematics
1 answer:
beks73 [17]3 years ago
3 0
The width of the rectangle is 2 meters
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Find two numbers such that one exceeds the other by 11 and their sum is 73.
Whitepunk [10]

Answer: 31 & 42

<u>Step-by-step explanation:</u>

1st #: x

2nd #: x + 11

1st# + 2nd# = sum

 x    +  x + 11 =  73

         2x + 11 = 73

         2x        = 62

           x          = 31


2nd #: x + 11   = 31 + 11   = 42

5 0
3 years ago
An amount of #550,000.00 was realised when a principal,x was saved 2% simple interest for 5 years. Find the value of x​
Zarrin [17]

Answer:

x = 250,000

Step-by-step explanation:

A = P(1 + rt)

550,000 =  x (1 +2% x 60)

550,000/(1 +2% x 60) = 250,000

x = 250,000

<u>Check your answer</u>

A = 250,000 (1+2%x60)

A = 550,000

pls mark brainliest

5 0
3 years ago
Determine the values of xfor which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001.(Enter
MrMuchimi

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

R_{3} = (x) = (e^z /4!)x^4

Since the aim is R_{3}(x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

3 0
3 years ago
A null hypothesis can only be rejected at the 5% significance level if and only if:
Over [174]
Hi,

Your answer would be B 

Hoped I Helped
6 0
4 years ago
Read 2 more answers
A horse is shown in the scale drawing the height of the horse in the drawing is 4.5 inches the scale that maps the drawing to th
sladkih [1.3K]

Answer: 6.75 feet.

Step-by-step explanation: 4.5 x 1.5

5 0
3 years ago
Read 2 more answers
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