If two different data sets have the same mean, the one with a wider range gives a better representation of its data.
2 answers:
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*The diagram is in the attachment
Answer:
q = 2√14
Step-by-step explanation:
To determine the value of q, apply the leg rule/geometric mean theorem, which is:
Hypotenuse/leg = leg/part
Hypotenuse = 10 + 4 = 14
Leg = q
Part = 4
Plug in the values into the equation:
14/q = q/4
Cross multiply
q*q = 14*4
q² = 56
q = √56
q = √(4*14)
q = 2√14
Treat the matrices on the right side of each equation like you would a constant.
Let 2<em>X</em> + <em>Y</em> = <em>A</em> and 3<em>X</em> - 4<em>Y</em> = <em>B</em>.
Then you can eliminate <em>Y</em> by taking the sum
4<em>A</em> + <em>B</em> = 4 (2<em>X</em> + <em>Y</em>) + (3<em>X</em> - 4<em>Y</em>) = 11<em>X</em>
==> <em>X</em> = (4<em>A</em> + <em>B</em>)/11
Similarly, you can eliminate <em>X</em> by using
-3<em>A</em> + 2<em>B</em> = -3 (2<em>X</em> + <em>Y</em>) + 2 (3<em>X</em> - 4<em>Y</em>) = -11<em>Y</em>
==> <em>Y</em> = (3<em>A</em> - 2<em>B</em>)/11
It follows that
Similarly, you would find
You can solve the second system in the same fashion. You would end up with