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3 years ago

Identify whether each phrase is an expression, equation, or inequality.

Mathematics

2 answers:

OverLord2011 [107]3 years ago

8 0

Answer:

swich the one attached to equation with the one attached to expression

Step-by-step explanation:

an equation need to have an equals sign, an expression doesnt.

Pavlova-9 [17]3 years ago

5 0

Answer:

Step-by-step explanation:

Equation= 8>h

Inequality= 10=d

Expression =7<em>f2</em>

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Find the sticker price and dealer's cost for the MT-5 Sedan with a base price of $10,600.00. Options cost $542.00, $140.00, $318

Bas_tet [7]

<h3>Answer:</h3>

sticker: $12,620
dealer's cost: $10,712

<h3>Step-by-step explanation:</h3>

The total cost of options is the sum of their individual costs.

total options = $542 +140 +318 +580 = 1580

The sticker price is ...

sticker price = base price + total options + destination charge

= $10600 +1580 +440

sticker price = $12,620

The dealer cost is ...

dealer cost = 82% × base price + 100% × total options + destination charge

= 0.82·$10600 +1580 +440

dealer cost = $10,712

4 0

2 years ago

Helpppp me please!!!

Semenov [28]

To find the value of q, we need to find d(-8). Put another way, we need to find the value of d(x) when x = -8

$d(x) = -\sqrt{\frac{1}{2}x+4}$

$d(-8) = -\sqrt{\frac{1}{2}(-8)+4}$

$d(-8) = -\sqrt{-4+4}$

$d(-8) = -\sqrt{0}$

$d(-8) = 0$

So this means q = 0. Note that -0 is just 0.

===========================================

The value of r will be a similar, but now we use f(x) this time.

Plug in x = 0

$f(x) = \sqrt{\frac{1}{2}x+4}$

$f(0) = \sqrt{\frac{1}{2}*0+4}$

$f(0) = \sqrt{0+4}$

$f(0) = \sqrt{4}$

$f(0) = 2$

Therefore, r = 2.

===========================================

For s, we plug x = 10 into f(x)

$f(x) = \sqrt{\frac{1}{2}x+4}$

$f(10) = \sqrt{\frac{1}{2}*10+4}$

$f(10) = \sqrt{5+4}$

$f(10) = \sqrt{9}$

$f(10) = 3$

So s = 3.

===========================================

Finally, plug x = 10 into d(x) to find the value of t

$d(x) = -\sqrt{\frac{1}{2}x+4}$

$d(10) = -\sqrt{\frac{1}{2}(10)+4}$

$d(10) = -\sqrt{5+4}$

$d(10) = -\sqrt{9}$

$d(10) = -3$

A shortcut you could have taken is to note how d(x) = -f(x), so this means

d(10) = -f(10) = -9 since f(10) = 9 was found in the previous section above.

Whichever method you use, you should find that t = -3.

===========================================

<h3>In summary:</h3><h3>q = 0</h3><h3>r = 2</h3><h3>s = 3</h3><h3>t = -3</h3>

8 0

2 years ago

In 1923, a certain country underwent one of the worst periods in history of hyperinflation, which is extraordinarily large inf

alexgriva [62]

Answer: 3.498 * 10^26 % ; 16.9% per day

Step-by-step explanation:

Inflation rate = 11,000 per month

Hence, price after a month :

Final price = initial price (1 + rate)

Final price = 1 + 11000/100

Final price = (1 + 110) * initial price

Final price = 111 times the initial price

Hence inflation over the 12 month period :

(111)^12 = 3.498 * 10^24

(3.498 * 10^24) * 100% = 3.498 * 10^26 %

The daily inflation rate :

Number of days = 30

30th root of 3.498 * 10^24 = 1.169

(1.169 - 1) = 0.169

0.169 * 100% = 16.9% per day

5 0

2 years ago

4x + y = 2<br> I need to solve the literal equation for y.

Mama L [17]

Answer: y=2−4x

Step-by-step explanation:

When solving for y in this problem(4x+y=2) we need to get y by itself in the equation. To do this we need to move 4x over to the right side of the equation. To do this we subtract, 4x from both sides of the equation.

7 0

2 years ago

A survey conducted in July 2015 asked a random sample of American adults whether they had ever used online dating (either an onl

Nadusha1986 [10]

Answer: $(0.081,\ 0.163)$

Step-by-step explanation:

Let $\hat{p}$ be the sample proportion.

As per given , we have

n= 411

$\hat{p}=\dfrac{50}{411}=0.121654501217\approx0.122$

Standard error : se=0.016

Critical value for 99% confidence : $z_{\alpha/2}=2.576$

Confidence interval for population proportion :-

$\hat{p}\pm z_{\alpha/2} (se)\\\\=0.122\pm (2.576)(0.016)\\\\=0.122\pm0.041216\\\\=(0.122-0.041216,\ 0.122+0.041216)\\\\=(0.080784,\ 0.163216)\approx(0.081,\ 0.163)$

Hence, the 99% confidence interval for the proportion of all US adults ages 55 to 64 to use online dating : $(0.081,\ 0.163)$

8 0

3 years ago