<h3>Given</h3>
- a cone of height 0.4 m and diameter 0.3 m
- filling at the rate 0.004 m³/s
- fill height of 0.2 m at the time of interest
<h3>Find</h3>
- the rate of change of fill height at the time of interest
<h3>Solution</h3>
The cone is filled to half its depth at the time of interest, so the surface area of the filled portion will be (1/2)² times the surface area of the top of the cone. The filled portion has an area of
... A = (1/4)(π/4)d² = (π/16)(0.3 m)² = 0.09π/16 m²
This area multiplied by the rate of change of fill height (dh/dt) will give the rate of change of volume.
... (0.09π/16 m²)×dh/dt = dV/dt = 0.004 m³/s
Dividing by the coefficient of dh/dt, we get
... dh/dt = 0.004·16/(0.09π) m/s
... dh/dt = 32/(45π) m/s ≈ 0.22635 m/s
_____
You can also write an equation for the filled volume in terms of the filled height, then differentiate and solve for dh/dt. When you do, you find the relation between rates of change of height and area are as described above. We have taken a "shortcut" based on the knowledge gained from solving it this way. (No arithmetic operations are saved. We only avoid the process of taking the derivative.)
Note that the cone dimensions mean the radius is 3/8 of the height.
V = (1/3)πr²h = (1/3)π(3/8·h)²·h = 3π/64·h³
dV/dt = 9π/64·h²·dh/dt
.004 = 9π/64·0.2²·dh/dt . . . substitute the given values
dh/dt = .004·64/(.04·9·π) = 32/(45π)
Answer:
Dependent
Step-by-step explanation:
He cant choose a pencil that she already gave him.
Answer:
The number of tile for which the cost is same route to nearest tile is 49 .
Step-by-step explanation:
Given as :
The cost which Joshua will pay for tile at one store = $ 0.99 per tile + $ 25 for tile saw
The cost which Joshua will pay for tile at another store = $ 1.50 per tile only
Let The number of tile for which the cost is same route to nearest tile = n
So, According to question
$ 0.99 × number of tile + $ 25 = $ 1.50 × number of tile
or, $ 0.99 × n + $ 25 = $ 1.50 × n
or, $ 1.50 × n - $ 0.99 × n = $ 25
I.e 0.51 × n = $ 25
∴ n = 
I.e n = 49.01 ≈ 49
So, The number of tile for which the cost is same route to nearest tile = n = 49
Hence The number of tile for which the cost is same route to nearest tile is 49 . Answer
Answer:
d
Step-by-step explanation:
The answer would be 3.5 or 7/2. If I interpreted your question correctly. Mark as brainliest?
