Answer:
1) ΔACD is a right triangle at C
=> sin 32° = AC/15
⇔ AC = sin 32°.15 ≈ 7.9 (cm)
2) ΔABC is a right triangle at C, using Pythagoras theorem, we have:
AB² = AC² + BC²
⇔ AB² = 7.9² + 9.7² = 156.5
⇒ AB = 12.5 (cm)
3) ΔABC is a right triangle at C
=> sin ∠BAC = BC/AB
⇔ sin ∠BAC = 9.7/12.5 = 0.776
⇒ ∠BAC ≈ 50.9°
4) ΔACD is a right triangle at C
=> cos 32° = CD/15
⇔ CD = cos32°.15
⇒ CD ≈ 12.72 (cm)
Step-by-step explanation:
your final answer should be.... -3 • (61c - 70)
The first step is to find the relationship between the square base and the surface area.
Surface area (SA) = area of the square (SS) + area of triangles.4(AT)
Thus we can conclude area of triangles 4(AT) = SA - SS = 864 - (18*18)
4(AT) = 864 - 324 = 540
Each triangle = 540/4 = 135 square in.
An area of one triangle (AT)= (base* slant height)/2
The base = 18 in.
<span>slant height = 2(AT)/base = 2(135)/18 = 15</span>
