The solution to the given compound inequality 2x - 3 < x + 2 ≤ 3x + 5 is 5 > x ≥ -3/2
<h3>Compound inequality</h3>
2x - 3 < x + 2 ≤ 3x + 5
solve differently
2x - 3 < x + 2
2x - x < 2 + 3
x < 5
x + 2 ≤ 3x + 5
x - 3x ≤ 5 - 2
-2x ≤ 3
x ≥ 3/-2
x ≥ -3/2
Therefore, the solution of the compound inequality is 5 > x ≥ -3/2
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Answer:
The slope is -1/2
Step-by-step explanation:
Hope it helps :3
Answer:
Simplify {4}^{2}42 to 1616.
-16+2\times -4\times -5-2\times {2}^{3}−16+2×−4×−5−2×23
Simplify 2\times -42×−4 to -8−8.
-16-8\times -5-2\times {2}^{3}−16−8×−5−2×23
Simplify 8\times -58×−5 to -40−40.
-16-(-40)-2\times {2}^{3}−16−(−40)−2×23
Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}xaxb=xa+b.
-16-(-40)-{2}^{4}−16−(−40)−24
Simplify {2}^{4}24 to 1616.
-16-(-40)-16−16−(−40)−16
Remove parentheses.
-16+40-16−16+40−16
Simplify -16+40−16+40 to 2424.
24-1624−16
Simplify.
8
Step-by-step explanation:
hope it helps :)
