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Harman [31]
3 years ago
5

A professor gives a multiple choice exam where each question has four choices. The professor decides not to count a question aga

inst students if the class as a whole does worse on the question than they would have done simply by guessing. That is, if significantly less than 25% of the students answer a question correctly, then that question won't count against them.
Let p represent the proportion of students that would correctly answer the question.
Which of the following is an appropriate set of hypotheses for such a significance test?

ANSWER: H0​:p=0.25
Ha​:p<0.25​
Mathematics
2 answers:
Korvikt [17]3 years ago
6 0

Answer:

H0: p<0.25

Alternate hypothesis  H1: p>=0.25

Step-by-step explanation:

The null hypothesis of the question basically depends on the problem statement.

Here, the problem statement is that if  less than 25% of the students answer a question correctly, then that question won't count against them.

Hence, null hypothesis would be

H0: p<0.25

Alternate hypothesis  H1: p>=0.25

devlian [24]3 years ago
3 0

Answer:Z=1.5

Step-by-step explanation:

Khan academy

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Kathy has 30 coins, consisting of dimes and quarters that total $5.10. How many coins of each type does she have?
Aliun [14]
The answer is 92 because that is what it is
4 0
3 years ago
HURRY QUICKLY SOMEONE PLEASE HELP ME ANSWER THIS QUESTION (10 POINTS)
nirvana33 [79]

Answer:

should be 489.13

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Help 20 pts its really hard for me
matrenka [14]

Answer:

7 is what percent of 30

is = 7

of = 30

% = x

Step-by-step explanation:

x/100 = 7/30

cross multiply

(30)(x) = (7)(100)

30x = 700

x = 700/30

x = 23 1/3% or 23.33%

i hope that helps

5 0
3 years ago
Read 2 more answers
Write a number between 80 and 100 that has exactly 3 factors, one of which is a 5
Flura [38]
Answer:

answer is 90

Explanation:

Here 5 is one of the 4 prime factors, so dividing the lower (80) and upper limit (100) by 5 we have new lower limit 16 and new upper limit 20.

So the product of other 3 factors should be greater than 16 and less than 20.

And we can have it from 18 only. Hence the number is 90.

The numbers between 80 and 100 having factor 5 are

<span>80,85,90,95,100</span>

<span>16=<span>24</span></span>

<span>17=17</span>

<span>18=2×3×3</span>

<span>19=19</span>

<span>20=<span>22</span>×5</span>

<span>90=2×<span>32</span>×<span>5</span></span>

<span><span>
</span></span>

5 0
4 years ago
Math Help. Greatly Appreciated
Triss [41]
So we know that the perimeter is 1260 feet and that the length is 100 more than the width, but we don't know that the width is.
So we're going to start with finding the width.
w = (x + x + 100) = 1260
from there we need to combine like terms
x + x = 2x
now we have
2x + 100  = 1260
From there, we will need to remove 100 from both sides, leaving us with
2x = 1160
now we'll need to divide both sides by 2
2x \div 2x = x
1160 \div 2 = 580
We now know that the width is 580, or more simply put, x=580.

Finding the length will be the easy part, as we know that it is just 100 more than the width
580 + 100 = 680
If you want an easier way of finding the length, just subtract the width from the perimeter.
1260 - 580 = 680
Leaving the final answer to be
Width = 580
Length = 680

3 0
3 years ago
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