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kkurt [141]
3 years ago
9

Yea someone explain/solve this...

Mathematics
2 answers:
xenn [34]3 years ago
6 0

           \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

      <em>[refer to attachment for question ~]</em>

<em />

<em />\rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

First of all, We need to multiply by the denominator (10) on both sides:-

\longmapsto\sf{\displaystyle\frac{-x+8}{10} \times10=-7\times10}

On the left-hand side, the 10s cancel as follows:-

\longmapsto\sf{-x+8=-7\times10}

On the right-hand side, we multiply -7 times 10:-

\longmapsto\sf{-x+8=-70}

Subtract 8 on both sides:-

\longmapsto\sf{-x=-70-8}

We get

  \longmapsto\sf{-x=-78}

And finally, Divide by -1 on both sides:-

\longmapsto\sf{x=78}

<h3>Good luck with your studies.</h3>

\rule{300}{1}

AleksandrR [38]3 years ago
5 0

Answer:

x = 78

Step-by-step explanation:

Multiply to remove the fraction, then set equal to 0 and solve.

Brainliest pls

alr thank you have a great day

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Answer:

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Let <em>X</em> = diameters of ball bearings.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 25.1 mm and standard deviation, <em>σ</em> = 0.08 mm.

To compute the probability of a Normally distributed random variable we need to first convert the raw scores to <em>z</em>-scores as follows:

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(a)

Compute the probability of <em>X</em> < 25.0 mm as follows:

P (X < 25.0) = P ((X - μ)/σ < (25.0-25.1)/0.08)

                    = P (Z < -1.25)

                    = 1 - P (Z < 1.25)

                    = 1 - 0.8944

                    = 0.1056

*Use a <em>z</em>-table for the probability.

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(b)

The 10th percentile implies that, P (X < x) = 0.10.

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P (X < x) = 0.10

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(c)

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                    = P (Z < 1.25)

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*Use a <em>z</em>-table for the probability.

Thus, the proportion of the ball bearings meeting the specification is 0.8881.

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