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diamong [38]
3 years ago
9

Mr Adams worked 78 hours during his six-day work week if he worked the same number of hours every day, how many hours did he wor

k in four days?
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Answer:

Mr Adams worked for 52 hours in four days.

Step-by-step explanation:

To get 52, you divide 78 and 6 and get 13. 13 is how many hours he worked a day. Since we need to find out how many hours he worked for 4 days, we add 13 4 times. If we add, the equation would look like this: 13+13+13+13=52. We can multiply also since it's easier. If we multiply our equation would be 13×4. Therefore, Mr Adams worked 52 hours in four days. Hope this helped

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Answer:

\huge\boxed{-19d + 8(7d - 14)=37d-112}

Step-by-step explanation:

-19d + 8(7d - 14)

use the distributive property: <em>a(b + c) = ab + ac</em>

<em></em>-19d + (8)(7d)+(8)(- 14)=-19d+56d-112<em></em>

combine like terms

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3 years ago
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finlep [7]

Here!

<h2>The answer is Option A!</h2>

(x + 2 \sqrt{3} i)(x - 2 \sqrt{3}i )

<h3>Why so??</h3>

Let's see what complex numbers are!

(x + 2  \sqrt{3 }i  )(x - 2 \sqrt{3}i ) \\  =  {x}^{2}  - 2 \sqrt{3} x + 2 \sqrt{3} x -  {(2 \sqrt{3} i)}^{2}  \\  =  {x}^{2}  -  {(2 \sqrt{3}i) }^{2}

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=  {x}^{2}  - 12 \times(  - 1)

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Step-by-step explanation:

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