Answer:
x = 0
Step-by-step explanation:
If one were to fold this figure in half over the line x = 0, then one would end up with a single figure, with no overhang. Hence x = 0 is the line of symmetry. Note; x = 0, can also be called the y-axis.
X=4.2
For the second equation, y=4x-25. Then you plug that into the first equation, which would form: 2x+2(4x-25)=17. Simplify. 2x+8x-25=17. 10x=42. x=4.2
Answer:
fourth option
Step-by-step explanation:
note that (
)(x)x) = 
=
← factorise numerator/ denominator
=
← cancel the common factor (2x + 1)
=
where x ≠ 0, - 
Answer:
1.5 hours
I traveled farther
2 miles
Step-by-step explanation:

My speed

Speed of my friend

Time passed for both me and my friend will be equal if we start at the same time and the combined distance covered by both of us will be 24 miles. Let
be the time taken to meet


So, we meet each other after 1.5 hours.
Distance traveled by me

Distance traveled by my friend

So, I traveled farther by
.