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GarryVolchara [31]
1 year ago
13

Answer from least to greatest 9 -11 -8 12 3

Mathematics
1 answer:
Thepotemich [5.8K]1 year ago
3 0
\begin{gathered} -11 \\ -8 \\ 3 \\ 9 \\ 12 \end{gathered}

remember a number is least when

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If tan x=.67, and cos x=.83, what is sin x
Alexxandr [17]

Answer:

0.56

Step-by-step explanation:

                                  sin x

tan x is defined as -------------

                                  cos x

and we can solve this for sin x:  sin x = (cos x)(tan x)

which here is:  sin x = 0.83(0.67) = 0.56 (rounded up from 0.5561)

7 0
3 years ago
I need the answer for this exact question
denis23 [38]

Answer:

y=\frac{7}{2}x-20

Step-by-step explanation:

Let the equation of the line be y-y_1=m(x-x_1) where, 'm' is its slope and (x_1,y_1) is a point on it.

Given:

The equation of a known line is:

y=-\frac{2}{7}x+9

A point on the unknown line is:

(x_1,y_1)=(4,-6)

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is m_1=-\frac{2}{7}

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20

The equation of a line perpendicular to the given line and passing through (4, -6) is y=\frac{7}{2}x-20.

3 0
3 years ago
What number should be added to both sides of the equation to complete the square x^2+12x=11
maksim [4K]

36 should be added to both sides because 12/2= 6 then you square 6 to get 36 and that should be it.

5 0
3 years ago
1.9/10 times 3/6 then simplified
givi [52]
1) 0.095
2)0.1875
3)0.3
4)0.21875
5)0.133
6)0.66
7) 0.6
8)0.375
8 0
3 years ago
Suppose that a simulation with a six-sided number cube provided these results during testing.
lyudmila [28]
Theoretical probability:
1 ... (16 and 2/3) %
2 ... (16 and 2/3) %
3 ... (16 and 2/3) %
4 ... (16 and 2/3) %
5 ... (16 and 2/3) %
6 ... (16 and 2/3) %

Experimental results:
1 ... 18
2 ... 16
3 ... 16
4 ... 17
5 ... 16
6 ... 17

The total number of rolls in the experiment was

         (18 + 16 + 16 + 17 + 16 + 17)  =  100

so the expected frequency for each outcome was 16-2/3 times,
and the SIMULATION probabilities were

1 ... 18%
2 ... 16%
3 ... 16%
4 ... 17%
5 ... 16%
6 ... 17%

To me, this looks fantastically close.  The cube
could hardly be more fair than it actually is.










8 0
3 years ago
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