What about if you use the distributive property? You could do 1(x+13) because the 1 would distribute to the x and the 13 making it x+13. Hope that is helpful.
Let us write some multiples of 4.
4,8,12,16,20,24,28,32,36,40.
<h3>We can see that 12,16, 32,36 are the multiples of 4 those have odd numbers 1 and 3 at tens places.</h3>
Now, we need to check the numbers on ones places of those multiples we got.
<h3>Ae can see that at ones places we have 2 and 6 numbers.</h3>
If we find some more mutiples, we get same odd numbers at tens places and same even numbers 2 and 6 at ones places.
Answer:
x = all real numbers, infinite solutions
Step-by-step explanation:
4(x-2) + 7 = 4x - 1
Distribute
4x -8+7 = 4x-1
Combine like terms
4x -1 = 4x-1
Subtract 4x from each side
4x-1 -4x = 4x-1-4x
-1 = -1
This is always true so there are infinite solutions for x