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3 years ago

How do I determine the 50th term for the sequence -5, -1, 3, 7, 11

1 answer:

5 0

The sequence is going up by 4 so u have to multiply each term by four and the -5 is it’s 0th term as well it’s beginning so you have to input that in the equation as well
4(50) - 5 = 200 - 5 = 195
I’m not very good at explaining so I hope u get it

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Help me please solve the circled question show your work

Rasek [7]

Part 1) Use the fact that there are 12 inches in a foot

a) How many inches tall is a 7 foot basketball player?

we know that

1 foot=12 inches

so by proportion

$\frac{12}{1} \frac{inches}{foot} =\frac{x}{7} \frac{inches}{feet} \\ \\x=12*7\\ \\x=84\ inches$

therefore

the answer Part 1a) is

$84\ inches$

Part b) If a yard is a 3 feet long, how many inches are in a yard?

we know that

1 yard=3 feet

1 foot=12 inches

Convert 3 feet to inches

by proportion

$\frac{12}{1} \frac{inches}{foot} =\frac{x}{3} \frac{inches}{feet} \\ \\x=12*3\\ \\x=36\ inches$

therefore

the answer Part 1b) is

$36\ inches$

Part 2) At the farmer's market two pounds of peaches cost $4.20 How much will five pounds cost?

by proportion

$\frac{4.20}{2} \frac{\$}{pounds} =\frac{x}{5} \frac{\$}{pounds} \\ \\2*x=4.2*5\\ \\x=4.2*5/2=\$10.5$

therefore

the answer Part 2) is

$\$10.5$

Part 3) Janice mother gave her a ten dollars bill to buy five pounds each of bananas and apples at the grocery store. When she got there she found that bananas were 80 c per pound and apples were $1.40 per pound.

Did Janice's mother give her enough money? If so, should she receive any change? If not, how much more money does she need?

we know that

Find the cost of the bananas

$5\ pounds*0.80\frac{\$}{pounds}=\$4$

Find the cost of the apples

$5\ pounds*1.40\frac{\$}{pounds}=\$7$

Sum the cost of the bananas and the cost of the apples

$\$4+\$7=\$11$

$\$11 > \$10$ ------> Janice's mother didn't give her enough money

She needs more money

She needs-------> $\$11-\$10=\$1$

therefore

the answer part 3) is

She needs $\$1$ more

3 0

2 years ago

Great Amusements Park has been raising its ticket prices every year, as shown in the table below

Fiesta28 [93]

1.)

Between year 0 and year 1, we went from $50 to $55.

$55/$50 = 1.1

The price increased by 10% from year 0 to year 1.

Between year 2 and year 1, we went from $55 to $60.50.

$60.50/$55 = 1.1

The price also increased by 10% from year 1 to year 2. If we investigate this for each year, we will see that the price increases consistently by 10% every year.

The sequence can be written as an = 50·(1.1)ⁿ

2.) To determine the price in year 6, we can use the sequence formula we established already.

a6 = 50·(1.1)⁶ = $88.58

The price of the tickets in year 6 will be $88.58.

4 0

3 years ago

Zaid has a peculiar pair of four-sided dice. When he rolls the dice, the probability of any particular outcome is proportional t

Elden [556K]

Answer: a) $\bold{\dfrac{3}{16}}$ b) $\bold{\dfrac{1}{36}}$

Step-by-step explanation:

a) In order to get an even number, you have the 3 different scenarios:

1) Even, Even, Even, Even $\dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}$

2) Even, Even, Odd, Odd $\dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}$

3) Odd, Odd, Odd, Odd $\dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}$

Order doesn't matter

Add them up to get your answer: $\dfrac{1}{16}+\dfrac{1}{16}+\dfrac{1}{16}\quad =\large\boxed{\dfrac{3}{16}}$

b) If one die is a 2 and another is a 3 and the other two dice can be any number, then you have 1 possibility for a 2, 1 possibility for a 3, and 6 possibilities for each of the other two dice.

$\dfrac{1\times 1\times 6\times 6}{6^4}\quad =\dfrac{1}{6^2}\quad =\large\boxed{\dfrac{1}{36}}$

3 0

2 years ago

Find A={a,b,c} then find A*A.

Alenkasestr [34]

Assuming you want to do a cartesian product, then you basically form items (x,y) such that x is in set A, and y is in set A

More generally, A * B will consist of items of the form (x,y) such that x is in A and y is in B. However, we have B = A.

So,

A * A = {

(a,a), (a,b), (a,c)

(b,a), (b,b), (b,c)

(c,a), (c,b), (c,c)

}

I broke things up into separate rows to show that we can form a 3x3 table. Each row is a different x value from the set {a,b,c}. Each column is a different y value from the set {a,b,c}

In my opinion, this helps organize things much better than rather have it all on one single line like this

A * A = { (a,a), (a,b), (a,c), (b,a), (b,b), (b,c), (c,a), (c,b), (c,c) }

which in all honesty looks like a bit of a cluttered mess.

7 0

2 years ago

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14(4)÷(7)+5(17)-3 please help

Tanya [424]

14(4)÷(7)+5(17)-3 please help

218

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2 years ago

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