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PIT_PIT [208]
3 years ago
12

Give the coordinates of the point located halfway between (2,1) and (2,4)

Mathematics
1 answer:
strojnjashka [21]3 years ago
6 0
Wouldn't it be (2,2.5)???
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Find the x- and y- intercepts of the equation -x+5y=10.
mario62 [17]

Answer:

X Intercept: (-10,0), Y Intercept: (0,2)

Step-by-step explanation:

Well, firstly you need to rewrite the equation to make it easier. After rewriting it you have the equation y=x/5+2 by adding the x to the right side and dividing everything by 5. Now simply plug in your zeroes in their respective places. For the x intercept, your y value must equal 0 so we have the equation 0=x/5+2. After solving it, x must be -10 in order for our y value to be 0 getting us for the x intercept (-10,0). For the y intercept, your x value must equal zero so you simply subsitute zero in the equation for x which I will do here: y=0/5+2. If our x value is zero, consequently, our y value will be 2 getting us for the y intercept, (0,2).

4 0
2 years ago
Graph x^2+60x+256in^2​
Softa [21]

Answer:

44

Step-by-step explanation:

there you goooooo oooooooooooooooooo

8 0
3 years ago
What is the surface area of a cube whose edges are 11 inches long?
Dennis_Churaev [7]
Surface area is the total area of the surface. A cube has 6 surface, and each surface is the same. Each surface is a 11 by 11 square. Therefore there will be 6 11in. x 11in. surfaces. The math would be 11x11x6 =726.
8 0
3 years ago
Read 2 more answers
Find f (2b^2) for (x)=x^2-4x
BlackZzzverrR [31]

Answer:

A

Step-by-step explanation:

We are given the function:

f(x) = x^2 - 4x

And we want to find:

\displaystyle f(2b^2)

Substitute:

\displaystyle f(2b^2) =(2b^2)^2 -4(2b^2)

And evaluate:

\displaystyle \begin{aligned}  f(2b^2) &=(2b^2)^2 -4(2b^2) \\ &=(4b^4) +(-8b^2) \\ &= 4b^4 - 8b^2 \end{aligned}

In conclusion, our answer is A.

7 0
3 years ago
Equation of a Circle: Mastery Test
xenn [34]

Answer:

(x-1)^2+(y+1)^2=3

Step-by-step explanation:

x² + y2 - 2x + 2y - 1 = 0

add the 1 to get it to the other side of the equation

x² + y2 - 2x + 2y  = +1

group the x's and y's

(x² -2x) + (y2+2y) = +1

then you'll complete the  square on the -2x and + 2y. that just means divide by two and then raise it to the 2nd power.

so (-2/2)^2 and (+2/2)^2

(x²-2x+1)+(y2+2y+1) = 1+1+1

you add the one's to the other side because whatever is done to one side must be done to the other

you'll then need to factor again.

(x-1)^2+(y+1)^2=3

to factor it take one of your squared x's, the sign of the middle term within the parentheses , then the square root of the last term within the parentheses. remeber to put your ^2 (raised to the 2nd power) outside of the parentheses  when you finish.

7 0
3 years ago
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