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nikdorinn [45]
2 years ago
10

HELPP ASAP

Mathematics
1 answer:
elena55 [62]2 years ago
7 0

Answer:

(4, -5)

(3, -2)

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Use the appropriate normal distribution to approximate the resulting binomial distributions. A convenience store owner claims th
Naddika [18.5K]

Answer:

0.9256

Step-by-step explanation:

Given that a convenience store owner claims that 55% of the people buying from her store, on a certain day of the week, buy coffee during their visit

Let X be the number of customers who buy from her store, on a certain day of the week, buy coffee during their visit

X is Binomial (35, 0.55)

since each customer is independent of the other and there are two outcomes.

By approximation to normal we find that both np and nq are >5.

So X can be approximated to normal with mean = np = 19.25

and std dev = \sqrt{npq} \\=2.943

Required probability = prob that fewer than 24 customers in the sample buy coffee during their visit on that certain day of the week

= P(X (after effecting continuity correction)

= 0.9256

6 0
3 years ago
HELP ASAP PLEASEEEEEE
xz_007 [3.2K]
Supplementary and adjacent are the two correct choices. 

7 0
3 years ago
Urgente!!! Doy 20 puntos
andre [41]

Answer:

  1. 7
  2. 4
  3. -7, 0, +9

Step-by-step explanation:

Hope this helps

4 0
2 years ago
Yoki is running a 10-mile race. She runs at a steady speed and then slows down, stops to get a drink of water, and
kondor19780726 [428]
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4 0
3 years ago
Read 2 more answers
Katrina wants to estimate the proportion of adults who read at least 10 books last year. to do​ so, she obtains a simple random
Vaselesa [24]
E=Z*sqrt (p(1-p)/N), where E= error margin, p=proportion, N=sample size

Katrina's margin error at 85% confidence interval: E=1.96*sqrt (p(1-p)/100) = 0.196 sqrt (1(1-p))

Mathew's margin error at 99% confidence interval: E= 2.58*sqrt (p(1-p)/400) = 0.129 sqrt (p(1-p))

Since both obtained same estimate of proportion (that is, value of p), it can be seen that Mathew's estimate will have a small error (That is, 0.129 is smaller than 0.196). This can be attributed to larger sample size although a wider confidence (99%) interval was considered.
3 0
3 years ago
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