If the original side length is "s" and the original slant height is "h", the original surface area is
.. S = (base area) +(lateral area)
.. S = s² +(1/2)*(4s)*h
.. S = s(s +2h)
Now, if we make these replacements: s ⇒ 3s, h ⇒ h/5, we have
.. S' = (3s)(3s +2h/5)
.. S' = 9s² +(6/5)s*h . . . . . . . the formula for the modified area (in terms of original dimensions)
_____
Of course, in terms of the modified dimensions, the formula is the same:
.. S' = s'(s' +2h')
Answer:
110%
Step-by-step explanation:
because there are two different squares that represent a whole, each with ten sections, the most reasonable answer would be 110%. I hope this helps you!
Answer:
78º
Step-by-step explanation:
<u>Note</u> : -
In mathematics, the reference angle is defined as the acute angle and it is measuring less than 90 degrees. It is always the smallest angle, and it makes the terminal side of an angle with the
x - axis.
<u>S</u><u>t</u><u>e</u><u>p</u><u> </u><u>1</u> : -
Find where 192º lies in which quadrant.
192º lies in 3rd quadrant ( between
180º and 270º )
<u>S</u><u>t</u><u>e</u><u>p</u><u> </u><u>2</u> : -
Subtract : 270 - 192
270 - 192 = 78º
( Since, 192º is greater than 180º, is subtracted from 270º )
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u> : -
78º is the reference angle for 192º.
Answer:
ok im convuzed how do you buy a 90ft tree cuz that sounds fun
Step-by-step explanation:
pls lemme know
Answer:
625 metres
Step-by-step explanation:
Given the area function expressed as a(w)=-(w-25)^2+625.
The maximum area occurs at when da/dw = 0
da/dw = -2(w-25)
0 = -2(w-25)
-2(w-25) = 0
w - 25 = 0
w = 25
Substitute w = 25 into the modeled equation;
Recall a(w)=-(w-25)^2+625.
a(25)=-(25-25)^2+625
a(25) = 0+625
a(25) = 625
Hence the maximum area possible is 625 metres
