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jonny [76]
4 years ago
14

A scale model of the Vancouver Olympic cauldron is to be built in memory of the 2010 Olympics. If the scale to be used is 1:27,

how tall, in meters, should the model be if the actual cauldron is 11.5 meters tall?
Mathematics
1 answer:
timurjin [86]4 years ago
4 0

Answer:

23/54 meters

Step-by-step explanation:

Assuming that the scale model is smaller, then the scale model should be 1/27th of the actual thing. Therefore:

11.5/27

= 23/54 meters tall

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If Rebecca reads 2pages per minute, how many pages could she read in 2 1/2 hours?
Mamont248 [21]

Answer:

300

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Sboob wohs dna ten.esaelpemetaD ot og FG evah i naC
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3 years ago
(Algebra) What is the lowest common denominator of 3/8x and 5/18x?
attashe74 [19]

Answer: 3/8x

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4 0
3 years ago
Two forces with magnitudes of 90 and 50 pounds act on an object at angles of 30° and 160°, respectively. Find the direction and
Stels [109]
Force 1, F1 = 90, angle 30°

Force 2, F2 = 50, angle 160°

F1 = 90 cos(30) i + 90 sin (30) j
F2 = 50 cos (160) i + 50 sin (160) j

F1 = 90*0.866 i + 90*0.5 j
F2 = 50*(- 0.940) i + 50*0.342 j

F1 = 77.94 i + 45 j
F2 = -47 i +17.10 j

Resultant force, Fr = F1 + F2

Fr = [77.94 - 47.00] i +[45 +17.10]j = 30.94 i + 62.10 j

Magnitude = √[30.94 ^2 + 62.10^2] = 69.38 pounds

Direction  = arctan[62.10/30.94] = 63.52 °


7 0
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