Graph x^3 - 3x^2 + 2 = 0.1 - x What are the solutions of the equation?

Mathematics

1 answer:

liq [111]3 years ago

6 0

Answer:

$x=-0.6,x=1.52,x=2.08$

Step-by-step explanation:

Let $f(x)=x^3-3x^2+2$ .

and

$g(x)=0.1-x$

The graph of the two equations are shown in the attachment.

The points where the two graphs intersected are: $(-0.6,0.7),(1.52,-1.42),(2.08,-1.98)$

The x-coordinates of the intersection points are the solutions to $x^3-3x^2+2=0.1-x$ .

Therefore the solutions are: $x=-0.6,x=1.52,x=2.08$

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