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Vesna [10]
2 years ago
7

A box contains 20 miniature golf putt-putt balls; 10 are

Mathematics
1 answer:
stellarik [79]2 years ago
5 0

Answer: The answer is provided below

Step-by-step explanation:

From the question, a box contains 20 miniature golf putt-putt balls out of which 10 are yellow, 6 are red, and the remaining 4 are pink.

The probability of picking a red golf ball will be:

= 6/20 × 100

= 600/20

= 30%

If the red ball is replaced, the probability of picking a yellow golf ball will be:

= 10/20 × 100%

= 50%

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(PaperTowels)
DochEvi [55]

Answer:

<u>23 consumer.</u>

Step-by-step explanation:

Given:

Number Of Responses for Thirsty = 49

Number Of Responses for Clean = 24

Number Of Responses for Strong Ones = 15

Number Of Responses for PowerWash = 12

So,

The total number of Responses  = 49 + 24 + 15 + 12 = 100

So, the probability to prefer PowerWash = 12/100 = 0.12

For a group of 195 consumers:

prediction to prefer PowerWash paper towels = 0.12 * 195 = 23.4

So,

The number of consumers prefer PowerWash paper towels = <u>23 consumer</u>

7 0
3 years ago
-4(2p + 5) + 8p = -11
sweet-ann [11.9K]

Answer:

There are no values of P to make it true

Step-by-step explanation:

6 0
2 years ago
Changing Bases to Evaluate Logarithms In Exercise, use the change-of-base formula and a calculator to evaluate the logarithm.
Ymorist [56]

Answer:

\frac{3}{2}

Step-by-step explanation:

Changing Bases to Evaluate Logarithms

log_{16}(64)

Apply change of base formula'

log_b(a)= \frac{log a}{log b}

log term should be the numerator and denominator is the log base

log_{16}(64)

log_{16}(a)= \frac{log 64}{log 16}

64 is 4^3  and 16 is 4^2

log_{16}(a)= \frac{log 4^3}{log 4^2}

Move the exponent before log

\frac{3log 4}{2log 4}

top and bottom has same log so cancel it out

\frac{3}{2}

3 0
2 years ago
−4x+7y+5=0<br> x−3y=−5<br> ​ <br><br> How many solutions does the system have?
xeze [42]

   

Solution:  

Using Substitution Method:

-4x+7y=-5   (Equation 1)

x-3y=-5       (Equation 2)

get the value of x from Equation 2

x=3y-5     (Equation 3)  

Put the value of x from Equation 3 in Equation 1

-4(3y-5)+7y=-5

-4(3y)+20+7y=-5

-12y+7y=-5-20

-5y=-25

Negative sign on both sides cancels each other

y=25/5

y=5

Putting value of y in equation 3

x=3(5)-5

x=15-5

x=10

Therefore,   [x,y]=[10,5]

Using Elimination Method

-4x+7y=-5   (Equation 1)

x-3y=-5       (Equation 2)

Multiply equation 2 with -4 in order to eliminate the x term

-4(x-3y)=-5*4

-4x+12y=20     (Equation 3)

Adding Equation 1 and 3

-4x+7y=-5    

-4x+12y=20    

+    -     = -   (Change Of Sign with x and y terms)

-----------------

0x-5y = -25

-5y=-25

y=5  

Substituting y’s value is Equation 1

-4x+7(5)=-5

-4x+35=-5

-4x=-40

Cancellation of negative sign on both sides

x=40/4

x=10

[x,y]=[10,5]

3 0
2 years ago
How many ways can a librarian arrange 15 books on a top shelf if she has 20 books from which to pick?
Jlenok [28]
Use the permutation formula
nPr = (n!)/((n-r)!)
20P15 = (20!)/((20-15)!)
20P15 = (20!)/(5!)

The final answer is choice A

8 0
3 years ago
Read 2 more answers
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