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Vesna [10]
3 years ago
7

A box contains 20 miniature golf putt-putt balls; 10 are

Mathematics
1 answer:
stellarik [79]3 years ago
5 0

Answer: The answer is provided below

Step-by-step explanation:

From the question, a box contains 20 miniature golf putt-putt balls out of which 10 are yellow, 6 are red, and the remaining 4 are pink.

The probability of picking a red golf ball will be:

= 6/20 × 100

= 600/20

= 30%

If the red ball is replaced, the probability of picking a yellow golf ball will be:

= 10/20 × 100%

= 50%

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Which is the equation in slope-intercept form for the line that passes through (3, 7)
quester [9]

Answer:

y =  -  \frac{5}{3} x + 12

Step-by-step explanation:

First, rewrite the given equation in the form of y=mx+c.

m is the gradient while c is the y-intercept.

3x-5y=8

5y= 3x -8

y =  \frac{3}{5} x -  \frac{8}{5}

Thus, the gradient of the given equation is ⅗.

The product of the gradients of perpendicular lines is -1.

(gradient of line)(⅗) = -1

gradient of line= -1 ÷⅗

gradient of line= -  \frac{5}{3}

y =  -  \frac{5}{3} x + c

To find the value of c, substitute a coordinate.

When x=3, y=7,

7 =  -  \frac{5}{3} (3) + c

7= -5 +c

c= 7+5

c= 12

Hence, the equation of the line is y =  -  \frac{5}{3} x + 12.

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3 years ago
Write -3 11 as a decimal number.<br> .<br> 16
mixas84 [53]

Answer:   i dont know

Step-by-step explanation:ok i am srry

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3 years ago
6(m-1) = 3(3m + 2) Show all work
nordsb [41]

Answer:

\boxed{\sf m = -4}

Step-by-step explanation:

\sf Solve \:  for  \: m: \\  \sf \implies 6 (m - 1) = 3 (3 m + 2) \\  \\  \sf Expand \:  out  \: terms \:  of \:  the \:  left  \: hand \:  side: \\  \sf \implies 6 m - 6 = 3 (3 m + 2) \\  \\  \sf Expand \:  out  \: terms  \: of  \: the  \: right \:  hand \:  side: \\  \sf \implies 6 m - 6 = 9 m + 6 \\  \\  \sf Subtract \:  9 m  \: from  \: both  \: sides: \\  \sf \implies (6 m - 9 m) - 6 = (9 m - 9 m) + 6 \\  \\  \sf 6 m - 9 m = -3 m: \\  \sf \implies -3 m - 6 = (9 m - 9 m) + 6 \\  \\  \sf 9 m - 9 m = 0: \\  \sf \implies -3 m - 6 = 6 \\  \\  \sf Add  \: 6 \:  to \:  both  \: sides: \\  \sf \implies (6 - 6) - 3 m = 6 + 6 \\  \\  \sf 6 - 6 = 0: \\  \sf \implies -3 m = 6 + 6 \\  \\  \sf 6 + 6 = 12: \\  \sf \implies -3 m = 12 \\  \\  \sf Divide  \: both  \: sides  \: of \:  -3 m = 12 \:  by \:  -3: \\  \sf \implies  \frac{ - 3m}{ - 3}  =  \frac{12}{ - 3}  \\  \\  \sf \frac{ - 3}{ - 3} = 1: \\  \sf \implies m =  \frac{12}{ - 3}  \\  \\  \sf -  \frac{12}{3}  =  - 4 :  \\  \sf \implies m =  - 4

7 0
3 years ago
Sharon needs 64 credits to graduate from her community college. So far she has earned 56 credits. What percent of the required c
Anit [1.1K]
Sharon has a percentage of 56/64*100= 87.5%
3 0
3 years ago
Read 2 more answers
WILL MARK THE CORRECT ANSWER BRAINLIEST!<br><br> Select all the correct answers:
stepladder [879]

Answer:

B, D

Step-by-step explanation:

Solve all equations:

A.

x-3x=-2x+4\\ \\-2x=-2x+4\\ \\0=4

This is false equality, so this equation has no solutions.

B.

x-\dfrac{1}{3}(3x)=0\\ \\x-x=0\\ \\0=0

This equality is true for all values of x, so this equation has infinitely many solutions.

C.

\dfrac{1}{3}x-3=4+2x\\ \\x-9=12+6x\\ \\x-6x=12+9\\ \\-5x=21\\ \\x=-\dfrac{21}{5}

This equation has the unique solution.

D.

3x+2-\dfrac{1}{3}(3x)=2+2x\\ \\9x+6-3x=6+6x\\ \\6x+6=6+6x\\ \\0=0

This equality is true for all values of x, so this equation has infinitely many solutions.

E.

x-\dfrac{1}{3}x+2=0\\ \\3x-x+6=0\\ \\2x=-6\\ \\x=-3

This equation has the unique solution.

8 0
3 years ago
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