Answer: Each adult’s meal costed $15
Step-by-step explanation:
This situation can be modeled by the following equation:
2a + 3c = 42, where a = the cost of an adult’s meal, and c = the cost of a child’s meal
Since we know from the problem that a child’s meal costs $4, we know c:
2a + 3(4) = 42
At this point, we can just solve the resulting equation for a:
2a + 3(4) = 42
= 2a + 12 = 42 (simplify 3(4))
= 2a = 30 (subtract 12 from both sides)
= a = 15 (divide both sides by 2)
So, the cost of each adult’s meal was $15.
The first odd number before 231 which would be on the same side of the hall is 229. The first odd number after would be 233.
On the odd side of the hall, the order would be room 229, room 231, room 233.
Answer:
See attachment
Step-by-step explanation:
First solve this like a normal equation:
-3x - 6 > 9
Add 6 to both sides:
-3x > 9 + 6
-3x > 15
Divide by -3 and remember to switch the inequality sign:
x < 15/(-3)
x < -5
Think about the graph of x = -5. It's a vertical line crossing the y-axis at x = -5. Now, we have x is less than -5. That means all the values less than -5 should be viable solutions. So, shade the part of the graph to the left of the vertical line.
Also, since we have x < -5 and not x ≤ -5, the line should be dotted.
See graph attached.
<em>~ an aesthetics lover</em>
My advice is don't smoke and make sure you don't keep the two close together. Hope this helped,