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2 years ago

True or False? No matter how the colonial government was setup, England had the ultimate say within the colonies

Mathematics

2 answers:

Anettt [7]2 years ago

3 0

True I think but I hope you get right

jasenka [17]2 years ago

3 0

Answer:

true

Step-by-step explanation:

England claimed the colonies, so they ruled over them.

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Consider △RST and △RYX. If the triangles are similar, which must be true? A. RY/YS=RX/XT=XY/TS B.RY/RS=RX/RT=XY/TS C.RY/RS=RX/RT

trasher [3.6K]

Answer:

B.RY/RS=RX/RT=XY/TS

Step-by-step explanation:

If Triangles RST and RYX are similar, then the ratio of their corresponding sides is:

$\dfrac{RS}{RY}= \dfrac{ST}{YX}=\dfrac{RT}{RX}\\$This could also be written by switching the numerator and denominators as:\\\dfrac{RY}{RS}= \dfrac{XY}{TS}=\dfrac{RX}{RT}$

Out of the given options, Option B is true.

3 0

3 years ago

Please hurry!!!

algol [13]

Answer:

Gallons of punch used = 4.94 gallons

Step-by-step explanation:

Given that:

Liters of punch purchased = 25 liters

Liters of punch left over = 6 liters

Liters of punch used = 25 - 6 = 19 liters

According to the given statement;

1 liter = 0.26 gallons

19 liters = 0.26*19 gallons

19 liters = 4.94 gallons

Hence,

Gallons of punch used = 4.94 gallons

7 0

2 years ago

Mort bought his house in 2004 for $279,000. it was recently appraised at $186,000. What is the approximate percent of decrease i

Natalka [10]

Answer:

33.3%

Step-by-step explanation:

(279,000 - 186,000) / 279,000 = 0.33333333333

0.33333333333*100= 33.3333333333

Formula used:

$V_{2} -V_{1}$ / $V_{2}$ × 100

V2= 279,000

V1= 186,000

7 0

3 years ago

-4x - 6y = 6<br> 4x + 6y = -4

Sloan [31]

Step-by-step explanation:

$-4x - 6y = 6$

$4x + 6y = -4$

To solve a system of equations, we can add the two equations and solve for one of the remaining variables -- let's try to eliminate the $x$ variable when we add the two equations together.

Right now, there's a $-4x$ term in the first equation, and a $4x$ term in the second equation, so if we add those together, we'll be able to eliminate the $x$ variable altogether and solve for $y$ .

However, when we also have a $-6y$ term in the first equation and $6y$ term in the second equation, so adding these together will also eliminate the $y$ term, leaving a $0$ on the left-hand side of the equation.

If we add the two numbers on the right side of the equation, we get $-2$ , which does not equal $0$ , meaning there are no solutions to this system of equations.