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2 years ago

On a coordinate plane, line D F goes through points (negative 1, negative 3) and (2, 3). Point G is at (negative 4, negative 4).

Mathematics

1 answer:

timofeeve [1]2 years ago

8 0

Answer:

Im sorry chile im trying to get more points

Step-by-step explanation:

but i think its the line passes thru y- axis point at point 0.4

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Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co

ycow [4]

Answer:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

$y= x^2 -6x +14$

We can complete the square like this:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

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3 years ago

What are the names of three planes that contain point G?

liubo4ka [24]

Answer:

B is the correct answer to your question

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2 years ago

Write in slope intercept form an equation of the line that passes through the given points

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2 years ago

Graph the line whose x-intercept is 8 and whose y-intercept is -9.

eduard

Answer: attached image

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1 year ago

Identify the solution of the system of equation<br> 2x+4=0<br> Y=5-3x

nexus9112 [7]

$2x+4=0\\
y=5-3x\\\\
2x=-4\\
y=5-3x\\\\
x=-2\\
y=5-3x\\\\
y=5-3\cdot(-2)\\
y=5+6\\
y=11\\\\
x=-2,y=11$

5 0

2 years ago

Read 2 more answers