Answer:
A
Step-by-step explanation:
We can use vertical line test to determine if a relation is a function.
<em>If a vertical line passes the graph at any point only once, then the relation is a function, if there is even 1 line that passes the graph at 2 points, then it is NOT a function.</em>
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The domain is the set of allowed x-values of the function. The range is the set of allowed y-values of the function.
- Looking at the graph, we see that there are a lot of vertical lines that cuts the graph two times. Suppose x=3, x=4, x= 5 etc. So it is not a function.
- As for domain, we see that curve swings from x = -8 to x = 8, so the domain is from -8 to 8.
- As for range, we that the curve stretches all the way from negative infinity to positive infinity, so the range is the set of all real numbers.
Correct answer is A
Collinear points lie on the same line. So, you must look for other points that lie on the line that connects A and N. If you start from A and continue along that line, you can see that, after N, you will meet points M and F.
So, those points are collinear with A and N.
Answer:
x=9
Step-by-step explanation:
Answer:
<em>p = ± q / 5r + 8; Option D</em>
Step-by-step explanation:
We are given the following equation; q^2 / p^2 - 16p + 64 = 25r^2;
q^2 / p^2 - 16p + 64 = 25r^2 ⇒ Let us factor p^2 - 16p + 64, as such,
p^2 - 16p + 64,
( p )^2 - 2 * ( p ) * ( 8 ) + ( 8 )^2,
( p - 8 )^2 ⇒ Now let us substitute this into the equation q^2 / p^2 - 16p + 64 = 25r^2 in replacement of p^2 - 16p + 64,
q^2 / ( p - 8 )^2 = 25r^2 ⇒ multiply either side by ( p - 8 )^2,
q^2 = 25r^2 * ( ( p - 8 )^2 ) ⇒ divide either side by 25r^2,
q^2 / 25r^2 = ( p - 8 )^2 ⇒ Now apply square root on either side,
| p - 8 | = √( q^2 / 25r^2 ) ⇒ Simplify,
| p - 8 | = q / 5r,
| p | = q / 5r + 8,
<em>Answer; p = ± q / 5r + 8; Option D</em>
Answer:
2
Step-by-step explanation:
7.9-5.9= 2.0 the answer would be 2
