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nlexa [21]
3 years ago
8

⚠️Find the distance between points (-3, -4) and (2, 1)⚠️​

Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

x1 = 2 y1 = 1

x2 = 3 y2 = 2

The distance between AB is √(2)

Step-by-step explanation:

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Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal
Usimov [2.4K]

Answer:

a) We have that the significance is given by \alpha =0.01 and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case z_{crit}=2.33

So then the rejection region would be z>2.33

b) We have that the significance is given by \alpha =0.05, \alpha/2 =0.025 and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case z_{crit}=\pm 1.96

So then the rejection region would be z>1.96 \cup z

Step-by-step explanation:

Part a

We have that the significance is given by \alpha =0.01 and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case z_{crit}=2.33

So then the rejection region would be z>2.33

Part b

We have that the significance is given by \alpha =0.05, \alpha/2 =0.025 and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case z_{crit}=\pm 1.96

So then the rejection region would be z>1.96 \cup z

7 0
3 years ago
A=2 b=3 c=4<br><br> 1) ab - c =<br> 2) 6c - 2b=<br> 3) a + b - c + 5 =<br> 4) 7c - 2a =
bekas [8.4K]

Step-by-step explanation:

1)ab-c

=2(3)-4

=6-4

=2

2)6c-2b

=6(4)-2(3)

=24-6

=18

3)a+b-c+5

=2+3-4+5

=10-4

=6

5)7c-2a

=7(4)-2(2)

=28-4

=24

7 0
3 years ago
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F(x) = 2(x+3)2 -7<br><br><br> a= <br><br> h=<br><br> k=
vlabodo [156]

Answer:

Step-by-step explanation:

In vertex form, the equation is

y = a(x-h)^2 + k

So just read off the values!

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Answer:

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Step-by-step explanation:

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Answer:

p(2p-11q+24p^6)

Step-by-step explanation:

8 0
3 years ago
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