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1 year ago

Please help I dont understand

Mathematics

2 answers:

Tomtit [17]1 year ago

4 0

B) 9ft

The area of a square is us found by taking the length of a side and squaring it. For example, if 9 is the side length, we would find the area by doing 9^2 or 9 x 9. This gives us 81 which is the closest to 76.5.

Degger [83]1 year ago

3 0

Answer:

I think it is B

Step-by-step explanation:

mark me brainliest

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Analyze the expression and then choose the sentences describing whether the binomial theorem can be used to factor it. Check all

daser333 [38]

Answer:

Step-by-step explanation:

N is 3 bc #of terms minus 1

Exponents go from 3>2>x>none

Can be factored using binomial theorem

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2 years ago

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Graph the linear equation. Find the three points that solve the equation then plot on the graph. -y=-x+1

Vinil7 [7]

Answer:

Step-by-step explanation:

The first step will be to make y the subject of the formula, by multiplying both sides of the equation by -1.

y = x - 1

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To determine the three points that solve the equation, we can let x be;

0, 1, 2

When x =0, y = 0-1 = -1

When x = 1, y = 1-1 = 0

When x = 2, y = 2 - 1 = 1

Therefore, we have the following three sets of points that can be used to graph the given linear equation;

(0, -1)

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(2, 1)

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2 years ago

Convert: 3 ½ mi = ____ ft.

just olya [345]

Answer:

3.5 mi = 18480 ft

Step-by-step explanation:

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2 years ago

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Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

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stellarik [79]

Step-by-step explanation:

Since, x=8 and x=-5 are the roots.

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