The number 0 can be classified as what?
1 answer:
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Answer:
The experimental probability of rolling an odd number is 60%, which is 10% more than the theoretical probability.
Step-by-step explanation:
The complete question is:
Type the correct answer in each box. Use numerals instead of words. If necessary, use/ for the fraction bar(s).
A special 8-sided die is marked with the numbers 1 to 8. It is rolled 20 times with these outcomes.
3, 4, 5, 2, 7, 1, 3, 7, 2, 6, 2, 1, 7, 3, 6, 1, 8, 3, 5, 6
The experimental probability of rolling an odd number is _%, which is _% more than the theoretical probability.
Solution:
The possible outcomes of rolling an 8-sided die are:
S = {1, 2, 3, 4, 5, 6, 7, 8}
The odd numbers are:
Odd = {1, 3, 5, 7} = 4 outcomes
The theoretical probability of rolling an odd number is:
Now from the given 20 outcomes the odd values are:
Odd = {3, 5, 7, 1, 3, 7, 1, 7, 3, 1, 3, 5} = 12 outcomes
Compute the experimental probability of rolling an odd number as follows:
Thus, the experimental probability of rolling an odd number is 60%, which is 10% more than the theoretical probability.
The rectangular equation for given parametric equations x = 2sin(t) and y = -3cos(t) on 0 ≤ t ≤ π is which is an ellipse.
For given question,
We have been given a pair of parametric equations x = 2sin(t) and y = -3cos(t) on 0 ≤ t ≤ π.
We need to convert given parametric equations to a rectangular equation and sketch the curve.
Given parametric equations can be written as,
x/2 = sin(t) and y/(-3) = cos(t) on 0 ≤ t ≤ π.
We know that the trigonometric identity,
sin²t + cos²t = 1
⇒ (x/2)² + (- y/3)² = 1
⇒
This represents an ellipse with center (0, 0), major axis 18 units and minor axis 8 units.
The rectangular equation is
The graph of the rectangular equation is as shown below.
Therefore, the rectangular equation for given parametric equations x = 2sint and y = -3cost on 0 ≤ t ≤ π is which is an ellipse.
Learn more about the parametric equations here:
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Answer:
Step-by-step explanation:
In every rhombus, when you have two diagonal segment bisectors, you will always have a circumcentre showing all midpoints of both segment bisectors, plus, it measures 90° all around, so with that being said, you have your answer.
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