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k0ka [10]
3 years ago
8

PLEASE HELP FAST!!! 30 POINTS

Mathematics
1 answer:
vlabodo [156]3 years ago
3 0

Answer:

Slope: 1/2

Explanation: Slope=rise/run

Y-Intercept: 4

Explanation: Y-intercept is the Y value where X=0

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115/12

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(2x2 – 18)(x+3)(2 – 3) = 2x4 – 36x2 + 162
lubasha [3.4K]

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X=4

Step-by-step explanation:

I'm took lazy to explain it step by step sorry, but I'm positive that's the correct answer.

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HELP THIS IS FOR TODAY HELP!!!! THANK YOU TO WHOEVER ANSWER'S
Rzqust [24]

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Step-by-step explanation:

4 0
3 years ago
The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis
Firdavs [7]

Answer:

sin\theta_1 =  - \frac{2\sqrt{70}}{19}

Step-by-step explanation:

We are given that \theta_1 is in <em>fourth</em> quadrant.

cos\theta_1 is always positive in 4th quadrant and  

sin\theta_1 is always negative in 4th quadrant.

Also, we know the following identity about sin\theta and cos\theta:

sin^2\theta + cos^2\theta = 1

Using \theta_1 in place of \theta:

sin^2\theta_1 + cos^2\theta_1 = 1

We are given that cos\theta_1 = \frac{9}{19}

\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 =  \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 =  \dfrac{280}{361}\\\Rightarrow sin\theta_1 =  \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 =  +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}

\theta_1 is in <em>4th quadrant </em>so sin\theta_1 is negative.

So, value of sin\theta_1 =  - \frac{2\sqrt{70}}{19}

6 0
3 years ago
How do u know if a like is linear?
Sever21 [200]

Answer:

Step-by-step explanation:

Linear means strait but what are you asking ?

7 0
4 years ago
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