Answer:
Critical value: z = 1.28
The 80% confidence interval for the mean repair cost for the washers is between $46.487 and $82.033.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
So it is z with a pvalue of 1-0.1 = 0.9, so z = 1.28
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
So
The lower end of the interval is the mean subtracted by M. So 64.26 - 17.773 = $46.487.
The upper end of the interval is M added to the mean. So 64.26 + 17.773 = $82.033.
The 80% confidence interval for the mean repair cost for the washers is between $46.487 and $82.033.
<span>8d3 + (6d2 – 4d)
=</span><span>8d3 + 6d2 – 4d
=2d(4d^2 + 3d - 2)
=2d(2d - 1)(d + 2) ...simplify and this is your answer
</span>
Write out the expression 2 - (2x-7)^2. That's it.
But if you want to go further and remove the parentheses, first expand (2x-7)^2: (2x-7)^2 = 4x^2 - 28x + 49,
and then subtract this result from 2:
2 - (4x^2 - 28x + 49) (It's important to use parentheses here)
Now, following the distributive property of multiplication, remove the parentheses:
2 - 4x^2 + 28x - 49
Combining the constants, we get the final answer: - 4x^2 + 28x - 47
Let us assume the length of the rectangle = x
Width of the rectangular dog run = 888 feet
Area of the rectangular dog run = 208 square feet
We already know
Area = Length * Width
Length = Area/Width
= 208/888 feet
= 0.23 feet
So the length of the rectangular dog run is 0.23 feet.
Since you have commented that
you made a mistake in giving the question so the answer will also definitely
change but the procedure will remain the same.
Answer:
20,600,000,000
Step-by-step explanation:
When writing a number in standard notation from scientific notation, counting decimal places is important. In this case, the exponent of 10 is 10. That means the decimal place must be moved 10 places; since it is positive the decimal place should be moved to the right. Finally, fill any empty spaces when moving the decimal point with zeros.
